[SOLVED] Fatal Error and It's Killing Me

[phpretard]

Does anyone know why I would get this? Fatal error: Can't use function return value in write context

 

$SEARCH="AB";

if (!ereg('[^A-Z]', $SEARCH) && (strlen($SEARCH) = 2))){

$searchResult = mysql_query("
SELECT * FROM members WHERE 
LicState LIKE '%$SEARCH%' OR 
LicState2 '%$SEARCH%' OR 
LicState3 LIKE '%$SEARCH%' OR 
LicState4 LIKE '%$SEARCH%' ");}

if (!searchResult){die(mysql_error());}

$num_rows= mysql_num_rows($searchResult);

echo $num_rows." FOUND";

 

I am looking for: "1 FOUND" ...and I get: Fatal error: Can't use function return value in write context

 

Thank again!

 

[JasonLewis]

I'm going to assume it's on this line:

 

if (!ereg('[^A-Z]', $SEARCH) && (strlen($SEARCH) = 2))){

 

You are using the = operator, which is trying to write to the return value of strlen(). Make it == and the error should go away.

[phpretard]

I took your advise on both post (THANK YOU!)

 

I now get: mysql_num_rows(): supplied argument is not a valid MySQL result resource...on line 17

 

if (!ereg('[^A-Z]', $SEARCH) && (strlen($SEARCH) == 2)){

$searchResult = mysql_query("
SELECT * FROM members WHERE 
LicState LIKE '%$SEARCH%' OR 
LicState2 '%$SEARCH%' OR 
LicState3 LIKE '%$SEARCH%' OR 
LicState4 LIKE '%$SEARCH%' ");}

if (!searchResult){die(mysql_error());}

$num_rows= mysql_num_rows($searchResult); << -------- LINE 17

echo $num_rows." FOUND";

}

 

Any ideas on this?

[kenrbnsn]

You missed a "$" in this line:

<?php
if (!searchResult){die(mysql_error());}
?>

it should be

<?php
if (!$searchResult){die(mysql_error());}
?>

 

Ken