[SOLVED] posting data

[kev wood]

hello i am trying to post data from one php page to another using hidden form elements.  but saddly with no joy.

 

i have already used this technique in other parts of the site but the form i am trying to send the data with is generated by php and it is not working.

 

the variables that i am trying to post are posrted to this page with hidden form elements than used and i now trying to to post them on again for one final time.

 

here is the code i am trying to post the data with

 

$sql = ("SELECT * FROM $table WHERE id = $id");
$result = mysql_query($sql);

$row = mysql_fetch_array($result) or die(mysql_error());
echo "<form action=\"update.php\" method=\"post\">";
echo "Date: <input type=\"text\" name=\"date\" value=\"{$row['date']}\" /><br /><br>";
echo "Title:  <input type=\"text\" name=\"title\" value=\"{$row['title']}\" /><br /><br />";
echo "<input type=\"hidden\" name=\"dropdown2\" value=\"{$db['dropdown2']}\" /><br /><br />";
echo "<input type=\"hidden\" name=\"radio2\" value=\"{$table['radio2']}\" /><br /><br />";
echo "<input type=\"hidden\" name=\"id\" value=\"{$id['id']}\" /><br /><br />";
echo "Article:<br /><textarea cols=\"50\" rows=\"10\" name=\"article\" onkeyup=\"textLimit(this, 500)\">{$row['article']}</textarea><br />";
echo "<input type=\"submit\" />";
echo "</form>";

 

i know they are coming to this page as the data is need to connect to the db and that is working fine.  the id is being passed to the next page as i have echoed this out.  the are received on this page with this code

 

$id = $_POST['id'];
$db = $_POST['dropdown2'];
$table = $_POST['radio2'];

[Maq]

Did you just modify it to say 2 instead of 3?  I could have sworn you had the wrong names in the POST fields...

[kev wood]

yes it i was messing around with it before i posted it up sorry for the confusion. it still not working any how.

[Maq]

Well you're doing it correctly.  I don't see any syntax errors, could you show me where these values are generated

 

{$db['dropdown2']}
{$table['radio2']}
{$id['id']}

[kev wood]

when i try to echo out the results i get an c for the db var and an i for the table var were it gets these from i do not know.

 

here is the code were it is generated from

 

<form action="edit.php" method="POST">
<select name="dropdown2">
<option value="constructiondb">Construction</option>
<option value="electricaldb">Electrical</option>
<option value="technicaldb">Technical</option>
</select>
<br />
<select name="radio2">
<option value="internal">Internal News</option>
<option value="general">General News</option>
</select>
<br />
<input type="submit" />
</form>

[Maq]

Oh I see, use these instead:

$db['dropdown2'] = $db
$table['radio2'] = $table
$id['id'] = $id

[kev wood]

no that still dont work i get array printed out on the screen now.

[kev wood]

to get it to work in the section of code that has this

value=\"{$db['dropdown2']}\"

i simply changed it to this

value=\"$db\

the only reason i can think that it didnt work was to do with the information i was trying to pass on again was already being passed to this page using hidden form data.  if you can explain to me why this was happening that would be nice because although i have fixed it i do not understand what was causing the problem in the first place.