Whats going on with is_int(eger)

[unkwntech]

I have this code:

$key = str_split('LMELMETETEMSGSYL75B2');
foreach($key as $i)
{
if(!is_integer($i))
 {
	echo $i;
 }
}

but it is outputting:

LMELMETETEMSGSYL75B2

when it should read

LMELMETETEMSGSYLB

 

The point of this is to actually preform a function on the non-integer objects the echo is just for testing

[genericnumber1]

You could do...

<?php
$key = 'LMELMETETEMSGSYL75B2';
$new = preg_replace('#[0-9]+#', '', $key);
echo $new;
?>

[The Little Guy]

That is because each is being read as a string.

 

try this:

 

$key = str_split('LMELMETETEMSGSYL75B2');
foreach($key as $i){
$v = intval($i);
if($v == 0){
	echo $i;
}
}

[corbin]

You could also do:

 

$key = str_split('LMELMETETEMSGSYL75B2');
foreach($key as $i)
{
if(!((int) $i == $i))
           echo $i;
}

 

 

The reason is_int is returning false is because it checks the datatype, not the content.

[The Little Guy]

This works too:

 

$key = 'LMELMETETEMSGSYL75B2';
echo preg_replace('~d~','',$key);

 

as you can see there are many choices to choose from..