Q695 Posted November 29, 2008 Share Posted November 29, 2008 I'm getting a problem in this statement: SELECT * FROM shows WHERE 'show' = '1' ORDER BY rank ASC; my data dictionary is: photos Table comments: InnoDB free: 3072 kB Field Type Null Default Comments rank tinyint(4) No 2 location tinytext No car int(11) No shows Table comments: InnoDB free: 3072 kB Field Type Null Default Comments rank tinyint(4) No 2 location tinytext No show smallint(6) No What's wrong with the query in the where section, because I don't see where it is? There are two files that work almost exactly the same way, just two different pages. Link to comment https://forums.phpfreaks.com/topic/134784-solved-mysql-where-problem/ Share on other sites More sharing options...
Mchl Posted November 29, 2008 Share Posted November 29, 2008 SELECT * FROM shows WHERE `show` = '1' ORDER BY rank ASC; Use `` not '' around column names Link to comment https://forums.phpfreaks.com/topic/134784-solved-mysql-where-problem/#findComment-701878 Share on other sites More sharing options...
Q695 Posted November 30, 2008 Author Share Posted November 30, 2008 Issue solved . Thanks Mchl. Link to comment https://forums.phpfreaks.com/topic/134784-solved-mysql-where-problem/#findComment-702488 Share on other sites More sharing options...
Mchl Posted November 30, 2008 Share Posted November 30, 2008 Issue solved . So mark the topic as such Cheers Link to comment https://forums.phpfreaks.com/topic/134784-solved-mysql-where-problem/#findComment-702501 Share on other sites More sharing options...
fenway Posted December 1, 2008 Share Posted December 1, 2008 SELECT * FROM shows WHERE `show` = '1' ORDER BY rank ASC; Use `` not '' around column names Or, don't do either and don't use reserved keywords as column names. Link to comment https://forums.phpfreaks.com/topic/134784-solved-mysql-where-problem/#findComment-703281 Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.