bumba000 Posted December 9, 2008 Share Posted December 9, 2008 Hi All, I have made a form, an "insert.php" and a DB to go along with it. For now my form has only Fname, Lname, Address and phone. I need to add fields for Model, Descrip, Qty and Price. My DB has two tables. One called customer_invoice and one called Orders. Both have an ID record as well. I would like to have my form (with the name and address. . .) also have multiple fields for product model, descrip. . . How can I have many fields (product area) input into the db and have the same ID as the customer? Also, how can many fields use the same name? Is there a better way to do what I'm trying to accomplish? Thanks in advance, John Link to comment https://forums.phpfreaks.com/topic/136233-form-trouble/ Share on other sites More sharing options...
Maq Posted December 9, 2008 Share Posted December 9, 2008 Is the customer already logged in? Where do you store the ID? I assume you do not have much done. Can we at least see the code you have already? Link to comment https://forums.phpfreaks.com/topic/136233-form-trouble/#findComment-710641 Share on other sites More sharing options...
bumba000 Posted December 9, 2008 Author Share Posted December 9, 2008 Thanks for the reply. This isn't gonna be used with a site or online in any way. Just for our local customers and for my own php practice. This is what I have so far for my Create_Invoice.php <table width="94%" border="0" align="center" cellpadding="2"> <tr> <td width="10%"> </td> <td width="63%"><div align="center">Customer Information </div></td> </tr> <tr> <td class="style1">Name </td> <td><form action="insert.php" method="post"> <label> First <input name="firstName" type="text" id="firstName" size="20" /> </label> Last <label> <input name="lastName" type="text" id="lastName" size="20" /> </label> </td> </tr> <tr> <td class="style1">Adderess</td> <td><label>Street <input name="street" type="text" id="address" value="" size="40"></label><br /> <lable>City <input name="city" type="text" id="city" value="" size="40"> </lable><br /> <lable>State <input name="state" type="text" id="state" value="" size="5"> </lable> <lable>Zip<input name="zip" type="text" id="zip" value="" size="8"> </lable></td> </tr> <tr> <td class="style1">Phone</td> <td><input name="phone" type="text" id="phone" size="20" /><br /><br /> </td> </tr> <tr><td><label> <input name="site" type="radio" value="12volt"> 12Volt</label><label> <input name="site" type="radio" value="stomp"> Stomp</label></td><td><input type="submit" name="Submit" value="Submit"></form></td></tr> </table> This is the insert.php <?php $con = mysql_connect("localhost","root","iforgot1"); if (!$con) { die('Could not connect: ' . mysql_error()); } $date = date("F j, Y"); // March 10, 2001 mysql_select_db("Invoicing", $con); $sql="INSERT INTO customer_invoice (FirstName, LastName, Street, City, State, Zip, Phone, Date, Site) VALUES ('$_POST[firstName]','$_POST[lastName]','$_POST[street]','$_POST[city]','$_POST[state]','$_POST[zip]','$_POST[phone]', '$date','$_POST[site]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con) ?> Link to comment https://forums.phpfreaks.com/topic/136233-form-trouble/#findComment-710838 Share on other sites More sharing options...
bumba000 Posted December 13, 2008 Author Share Posted December 13, 2008 Bump Link to comment https://forums.phpfreaks.com/topic/136233-form-trouble/#findComment-714724 Share on other sites More sharing options...
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