jeff5656 Posted December 22, 2008 Share Posted December 22, 2008 If a user puts in a ' character and submits (i..e "Smith's heart rate was 55") it gives me: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Select Staff' )' at line 3 How do I modify the code to strip this character? Here's what I would need to modify: $dx1 = $_POST['dx1']; Quote Link to comment https://forums.phpfreaks.com/topic/138063-solved-stripping-the-character-after-a-post/ Share on other sites More sharing options...
ngreenwood6 Posted December 22, 2008 Share Posted December 22, 2008 You should always filter any variables that go into the database with mysql_real_escape_string like this: $dx1 = mysql_real_escape_string($_POST['dx1']); Quote Link to comment https://forums.phpfreaks.com/topic/138063-solved-stripping-the-character-after-a-post/#findComment-721636 Share on other sites More sharing options...
jeff5656 Posted December 22, 2008 Author Share Posted December 22, 2008 Thanks that solves it. Can I please ask though how would you do it for this (I am bad with figuring out quotation mark placement and this is inside sql="SELECT FROM ...etc" dx1 = '" . $_POST['dx1'] . "', dx2 = '" . $_POST['dx2'] . "', dx3 = '" . $_POST['dx3'] . "', etc. Quote Link to comment https://forums.phpfreaks.com/topic/138063-solved-stripping-the-character-after-a-post/#findComment-721643 Share on other sites More sharing options...
dennismonsewicz Posted December 22, 2008 Share Posted December 22, 2008 i would also look into error checking with PHP cause you don't just want to select something out of a DB without checking the $_POST vars Quote Link to comment https://forums.phpfreaks.com/topic/138063-solved-stripping-the-character-after-a-post/#findComment-721645 Share on other sites More sharing options...
ngreenwood6 Posted December 22, 2008 Share Posted December 22, 2008 I am not sure that I understand what you are trying to ask? Quote Link to comment https://forums.phpfreaks.com/topic/138063-solved-stripping-the-character-after-a-post/#findComment-721659 Share on other sites More sharing options...
premiso Posted December 22, 2008 Share Posted December 22, 2008 $string = "dx1 = '" . mysql_real_escape_string($_POST['dx1']) . "', dx2 = '" . mysql_real_escape_string($_POST['dx2']) . "', dx3 = '" . mysql_real_escape_string($_POST['dx3']) . "'"; That is how you would formulate if I gathered your question right. Quote Link to comment https://forums.phpfreaks.com/topic/138063-solved-stripping-the-character-after-a-post/#findComment-721668 Share on other sites More sharing options...
jeff5656 Posted December 22, 2008 Author Share Posted December 22, 2008 Thanks that works! Quote Link to comment https://forums.phpfreaks.com/topic/138063-solved-stripping-the-character-after-a-post/#findComment-721733 Share on other sites More sharing options...
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