[SOLVED] Run an external script after array?

[Graxeon]

I have this:

 

<?php
$URL = $_GET['url'];
$allowed_url = array("google.com","yahoo.com");
if(in_array($URL,$allowed_url))
{
   header("Location: http://video.".$URL."/videorankings?type=blogged&cr=usa&hl=en");
}else{
   header("Location: http://www.google.com/");
}
?>

 

But I want to run it with this in a separate PHP file:

 

<?php

   header("Location: http://video.".$URL."/videorankings?type=blogged&cr=usa&hl=en");

?>

 

So how can I call that second script through the first one like this:

 

<?php
$URL = $_GET['url'];
$allowed_url = array("google.com","yahoo.com");
if(in_array($URL,$allowed_url))
{
CALL 2nd PHP file from here
}else{
   header("Location: http://www.google.com/");
}
?>

 

I don't want the script to redirect to the 2nd one...I just want the second one to run after it's gone through the array check system thing.

[DarkWater]

Why?

[t_miller_3]

Can you not use:

 

<?php include(filename.php); ?>

 

I'm only new to php so excuse me if I'm completely wrong

[Graxeon]

Why?

 

Some of my other scripts don't work within the array script so I need to run it externally.

 

My team doesn't want me to share the script so that's why I have to ask in this manner .

 

Can you not use:

 

<?php include(filename.php); ?>

 

I'm only new to php so excuse me if I'm completely wrong

 

I tried this but it didn't work:

 

<?php
$URL = $_GET['url'];
$allowed_url = array("google.com","yahoo.com");
if(in_array($URL,$allowed_url))
{
include(file2.php);
}else{
   header("Location: http://www.google.com/");
}
?>

[corbin]

 

<?php
$URL = $_GET['url'];
$allowed_url = array("google.com","yahoo.com");
if(in_array($URL,$allowed_url))
{
header("Location: http://video.".$URL."/videorankings?type=blogged&cr=usa&hl=en");
}else{
   header("Location: http://www.google.com/");
}
?>

 

 

????

 

Guessing I'm misunderstanding the problem.

[opalelement]

include should work, did it give an error or anything?

[Graxeon]

include should work, did it give an error or anything?

 

Nope, just a blank page.

 

Guessing I'm misunderstanding the problem.

 

Oh...right I should explain what it's doing first.

 

Ok this script is checking to see if the inputs after "url=" are in the predefined list of "allowed" inputs:

 

<?php
$URL = $_GET['url'];
$allowed_url = array("google.com","yahoo.com");
if(in_array($URL,$allowed_url))
{
header("Location: http://video.".$URL."/videorankings?type=blogged&cr=usa&hl=en");
}else{
   header("Location: http://www.google.com/");
}
?>

 

If the input is in the predefined list, then this part of the script is run:

 

header("Location: http://video.".$URL."/videorankings?type=blogged&cr=usa&hl=en");

 

If the input is not in the list, then the user is redirected to "http://www.google.com"

 

Now...what I want to do is instead of having "header("Location: http://video.".$URL."/videorankings?type=blogged&cr=usa&hl=en");" within the same script, I want it to be on an external file.

 

So I should have 2 PHP files, the first one would be this:

 

<?php
$URL = $_GET['url'];
$allowed_url = array("google.com","yahoo.com");
if(in_array($URL,$allowed_url))
{
CALL 2nd PHP file from here
}else{
   header("Location: http://www.google.com/");
}
?>

 

The 2nd script would be:

 

<?php
//This can be any script, btw. My team doesn't allow me to share the script that I do want to put here, sorry.
   header("Location: http://video.".$URL."/videorankings?type=blogged&cr=usa&hl=en");

?>

 

That 2nd script would take whatever "allowed" input the user used in the first script and just run it through the 2nd script.

 

 

 

Does that make more sense? >.<

[corbin]

That's pretty much how including works.  http://php.net/include

 

file1.php

<?php

$x = 5;

include 'file2.php';

 

file2.php

<?php

echo $x;

 

 

Would put out 5.

[Graxeon]

I'm a newbie, can you show me how to do it with the scripts I provided, please?

 

I tried to mess around with it but it didn't output anything xD

[corbin]

Since your scripts are using header statements, they shouldn't print out anything but headers, which you won't see in a browser.

 

<?php
$URL = $_GET['url'];
$allowed_url = array("google.com","yahoo.com");
if(in_array($URL,$allowed_url))
{
    require 'file2.php'; //require is the same as include, but the script throws a fatal error if the file isn't able to be included.
}else{
   header("Location: http://www.google.com/");
}
?>

 

file2.php

<?php
//This can be any script, btw. My team doesn't allow me to share the script that I do want to put here, sorry.
   header("Location: http://video.".$URL."/videorankings?type=blogged&cr=usa&hl=en");

?>

[Graxeon]

It works, thank you very much.

 

PHPfreaks.com has sexy gurus in it

[corbin]

Creepy, but errr... You're welcome ;p.