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You have to echo it out using [m]date/m]

 

<?php
$newtime = strtotime("+2 hours",$a['time']);
echo date('H:i', $newtime);
?>

 

Should print it out right.

 

Just remember, we usually provide examples, it is up to you to take those examples and implement them correctly in your code, IE replacing "$oldtime" to be $a['time'].

Yup, I know about examples. I added that variable to show you better, as you won't know what $a['time'] means. I'm having problems with it not working the correct hour out.

 

<table width="100%" cellpadding="4" cellspacing="0" border="0">
<tr>
<td><font class="heading2">Start</font></td>
<td><font class="heading2">End</font></td>
<td><font class="heading2">Presenter</font></td>
</tr>
<?PHP
$q = mysql_query("SELECT * FROM `timetable` WHERE `day` = '".$_GET['day']."' ORDER BY `time` ASC");
while($a = mysql_fetch_array($q)){
$newtime = strtotime("+2 hours", $a['time']);
?>
    <tr>
    <td><?=$a['time'];?></td>
    <td><?=date('H:i', $newtime);?></td>
    <td><?=$a[presenter];?></td>
    </tr>
<?PHP } ?>
</table>

 

This is what I have dispayed:

17:00  02:00  Tom

 

 

Any ideas? The 02:00 should show 19:00.

Not sure why, I just ran the test on my server doing this:

 

<?php
$a['time'] = "17:00";
$newtime = date("H:i", strtotime($a['time'])+3600*2); // 3600*2 = 2 hours
echo "The time should be 19:00 and (drum role) the time is: " . $newtime;
die();
?>

 

Output:

The time should be 19:00 and (drum role) the time is: 19:00

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