[SOLVED] Function and Return Value - Problem

[dgywft]

Hey guys, I am having an issue making my own function. I want to run the following function:

 

function getFolder($sku) {

    if ( (strpos($sku, "P") === 0) || (strpos($sku, "P")) ) { $imgfolder = "print"; }

    if ( (strpos($sku, "E") === 0) || (strpos($sku, "E")) ) { $imgfolder = "eps"; }

    if ( (strpos($sku, "T") === 0) || (strpos($sku, "T")) ) { $imgfolder = "type"; }

    if ( (strpos($sku, "C") === 0) || (strpos($sku, "C")) ) { $imgfolder = "cloth"; }

    if ( (strpos($sku, "A") === 0) || (strpos($sku, "A")) ) { $imgfolder = "art"; }

    if ( (strpos($sku, "M") === 0) || (strpos($sku, "M")) ) { $imgfolder = "mm"; }

 

    return $imgfolder;

 

}

 

The function will not work as written here:

$theImagePath = "/img/". getFolder($sku) . "/" . $sku . "/";

 

 

Can anyone provide some pointers on the proper way to run this function as needed?

 

 

 

[Mark Baker]

So what exactly is it returning, and what are you expecting it to return?

[dgywft]

This is checking a sku number in my site. It them runs that function with the sku to see what type of product, then set the folder name (mm,print,eps), then return that value at end of function. Then back to my actual page thats running the function, I run it in that statement, then use the variable ($theImagePath) next line in a if statement:

 

-

 

$theImagePath = $serverPath ."/img/". getFolder($sku). "/" . $sku . "/";

               

if( file_exists($theImagePath) ) {

[trq]

What does the $sku variable typically contain? I have a feeling your function could be reduced to....

 

function getFolder($sku) {
  $arr = array("P" => "print","E" => "eps","T" => "type","C" => "cloth","A" => "art","M" => "mm");

  if (in_array($arr, $sku)) {
    return $arr[$sku];
  }

  return false;   

}