Easy IF Statement Help!

[stevens]

Hi there is something wrong with my if statement, please let me know what it is!! It doesnt echo denied! Im trying to only get accepted; if status doesnt = "test" and it is authorised.

[code]
$status = $_POST['status'];

if ((!strstr($response, "AUTHORISED"))||($status = "test")) {
    echo "denied";
}
else {
    echo "accepted";
}
[/code]

[micah1701]

$status = "test"

should be

$status == "test"

[Houdini]

Keep in mind that [b]=[/b] is an assignment operator what you want when checking values of a variable or array is a comparison operator which are [b]==[/b] and [b]===[/b] but [b]== [/b]being more commonly used for a normal string variable. This is a common error by those just starting out.

[stevens]

The status = "test" works fine, but i will change it to == anyway. The problem seems to be with the brackets and || maybe?

[micah1701]

where is the variable $response getting its value from?

your if/then statment is checking the string value in $response to see if it contains the word "AUTHORISED".

Where in your code is $response populated?
Also, the word is spelled "AUTHORIZED" with a 'z'

[Houdini]

Not really because what is happening is that you are assigning the value of 'test' to the variable $status regardless of what it was prior to that statement. If the $_POST['status'] was "" or nothing when it gets to $status='test' then PHP will assign the value on the right to the variable on the left whereas $status =='text' will check the value of $status and if it is 'test' then it will return true otherwise it would return false if it were"" or nothing and fail. Here is an example to illustrate what I just stated

[code=php:0]<?php
$status = "UH OH";
if($status==""){//remove the second = sign and retest to see the result it will execute the else statement
  echo "$status contains no printable characters";
}
elseif($status=="UH OH"){
  echo"The proper value of $status is in the \$status variable!";
}
else{
  echo"The \$status variable is not correctly set.";
}
?> [/code]

[stevens]

Houdini thankyou for your reply, i understand that now.

[stevens]

How can i make this return cost_check if they dont match?

This doesnt work:
[code]if (!$cost_check == $status) {
    echo "$cost_check";
}
else {
echo "ok";
     }
}[/code]

[cmgmyr]

[code]if ($cost_check != $status) {
    echo "error";
}else {
    echo "$cost_check";
}[/code]

[stevens]

D'oh!

Thanks.

[cmgmyr]

It's almost too simple  ;D