[SOLVED] Help extracting certain part of string..

[virtuexru]

Hey everyone .

 

I have a script that puts an HTML page into a variable called $data.

 

Basically, what I need to do now, is extract a certain part of the script into its own variables (array). There are six images that I need off the page to be put into separate variables.

 

Here is the code for the images:

 

<img src="http://somewebsite.com/website/website/pix/20081119/19667358_1.JPG?" width=96 height=72 border=0>
<img src="http://somewebsite.com/website/website/pix/20081119/19667358_2.JPG?" width=96 height=72 border=0>
<img src="http://somewebsite.com/website/website/pix/20081119/19667358_3.JPG?" width=96 height=72 border=0>

 

Now, say I wanted to JUST extract the BOLDED part, how would I go about doing that?

 

h**p://somewebsite.com/website/website/pix/20081119/19667358_3.JPG

 

Or maybe just extracting the whole URL would be easier? Either one would work.

 

Thanks in advance PHP Gurus!!

[premiso]

It can be done with regex using preg_match_all. But since I am not good at that here is an alternative way.

 

<?php
$string = '<img src="http://somewebsite.com/website/website/pix/20081119/19667358_1.JPG?" width=96 height=72 border=0>
<img src="http://somewebsite.com/website/website/pix/20081119/19667358_2.JPG?" width=96 height=72 border=0>
<img src="http://somewebsite.com/website/website/pix/20081119/19667358_3.JPG?" width=96 height=72 border=0>';

$strings = explode("border=0>", $string);

array_pop($strings);
$urlData = array();
foreach ($strings as $line) {
    list($data) = explode('" width=', $line);
    list(,$data) = explode('src="', $data);
    $urlData[] = explode('/', $data);
}

print_r($urlData);
?>

 

Should work. Untested.

 

 

Using regex would take out alot of the guessing game. Maybe someone will show you that, which would lower this to a couple lines.

[virtuexru]

Figured it out:

 

<?php
$pattern = "/src=[\"]?([^\"]?.*(jpg))[\"]?/i";
preg_match_all($pattern, $data, $images);
?>

[premiso]

Figured it out:

 

<?php
$pattern = "/src=[\"]?([^\"]?.*(jpg))[\"]?/i";
preg_match_all($pattern, $data, $images);
?>

 

Yep much nicer than my way =P

[virtuexru]

Figured it out:

 

<?php
$pattern = "/src=[\"]?([^\"]?.*(jpg))[\"]?/i";
preg_match_all($pattern, $data, $images);
?>

 

Yep much nicer than my way =P

 

Your way still worked, helped me figure out exactly what I needed. Thanks again!