[SOLVED] date function

[gish]

hi php freaks

 

How do I get the date function to echo its contents and how do I get a date function to echo out the same contents but one month in advance?

 

thanks gishaust

[Maq]

What type is your date stored in?  date()

 

$next_month = mktime(0, 0, 0, date("m")+1, date("d"), date("y"));
echo "Next month is ".date("m/d/y", $next_month); 
?>

[gish]

Sorry newbie what do yo mean by type? This is what I have so far?

 

echo date(mktime(0,0,0,$m,$y));

echo date(mktime(0,0,0,$m+1,$y));

 

but looking at what you had. I need to goto php.net and have another look.

[gish]

hi me again

 

(0, 0, 0, date("m")+1, date("d"), date("y")

 

 

is the m, d, y integers

[Maq]

Can you just post your code?  If you don't have any, do you want the current time? Input from the user?  What?

 

Sorry newbie what do yo mean by type?

 

I meant datatype.  Is it a timestamp stored in a DB, a string, integer, what?

[gish]

The only code I have is the one I have posted I.  All I want to do is print the current date, month, year and if I press a link it goes to the same date, next month, and current year.

 

 

Thanks of data type information

[Maq]

The only code I have is the one I have posted I.  All I want to do is print the current date, month, year and if I press a link it goes to the same date, next month, and current year.

 

 

Thanks of data type information

 

What format do you want to print the day, month, and year?  Here's a list of formats.

 

Current date:

 

$right_now = mktime(0, 0, 0, date("m"), date("d"), date("y"));
echo "Current date: ".date("m/d/y", $right_now); 
?>

 

I have no clue what you mean by, " if I press a link it goes to the same date, next month, and current year.", or how that even makes sense.

[gish]

I mean some think like this

 

$right_now = mktime(0, 0, 0, date("m"), date("d"), date("y"));
echo "Current date: ".date("m/d/y", $right_now); 

 

The output would be 6/2/2009

 

then you press a link <href>

 

Then the output would be 6/3/2009

 

In Australia is d/m/y

[Maq]

I think this is what you meant.

 

$add = isset($_GET['next']) ? 1 : 0;
$right_now = mktime(0, 0, 0, date("m")+$add, date("d"), date("y"));
echo "Current date: ".date("d/m/Y", $right_now); 
?>

Next month

Current Date

 

You could also do it easily in JS.

[gish]

Thanks that is what I was looking for.

One quick question I have been looking at this date

function.

 

  [mday]    => 17

 

I understand this tells me the day of the month 

How do I find out how many  days that are in a  month?

 

[Maq]

$lastday = mktime(0, 0, 0, 4, -31, 2000);
echo strftime("Last day in Feb 2000 is: %d", $lastday);
?>

 

It's all in the manual, mktime.

[gish]

thanks