[SOLVED] for loop echo every 7 counts

[FD_F]

how can i do for($d=0;$d<$i;$d++)  $i can be  20 for example  starting from 0,  that will  give output every 7 counts

[allworknoplay]

Well I don't know how often you want your loop to run? But let's say it loops 30 times.

 

 

$i = 30;

for ($d=0;$d<$i;$d++) {

   if($d == 7 || $d == 14 || $d == 21) {
echo "something";
}
        


}


}

[FD_F]

thanks for the idea but i dont know how often the loop runs it culd be even 150 times

 

 

[allworknoplay]

thanks for the idea but i dont know how often the loop runs it culd be even 150 times

 

 

 

Well my "for loop" works. All you have to do is just implement a calculation that correctly identifies

multiples of 7....

 

Then put the numerical answers into an array. And during the loop check the array values and if they

appear, then do an echo statement.

[genericnumber1]

You can do something like..

<?php
for($i = 0; $i < 50; ++$i) {
    if($i % 7 == 0) {
        echo $i;
    }
}

[Cosizzle]

genericnumber1 beat me to it but is correct, made this test.

 

$i = 30;
$divNum = 7;

for ($d=0; $d<$i; $d++) {

// something happening
echo 'count = '.$d.'<br/>';
echo 'divNum = '.$d % $divNum;
echo '<br/>';

if ($d % $divNum == 0) {
	echo 'true<br/>';
}
echo '<hr>';
}

[FD_F]

thanks for all the explains