in_array

[mbrown]

if(!in_array($ipaddressubnet,$ipaddresses))
....

 

That is part of my code portion of a page.

 

I would like to have many variables like $ipaddresssubnet, $ipaddresssubnet1, $ipaddresssubnet2, etc to see if it is in the $ipaddresses array

 

Can I do something like that with the in_array function?

[sasa]

http://hr.php.net/array_intersect

[mbrown]

I understand how this works but not sure completely how it is the right thing for me

[premiso]

array_search may help you, you can pass in an array and check if the values are in the array, if they are it returns you the indexes.

 

<?php
$ipSearch = array('192.168.0.1', '192.168.0.2', '192.168.9.1');
$ipaddresses = array('192.168.0.3', '192.168.0.2', '192.168.1.1', '192.168.9.1');

$found = array_search($ipSearch, $ipaddresses);

if (count($found) > 0) {
    foreach ($found as $key) {
           echo "{$ipaddresses[$key]} was found at index {$key}.<br />";
    }
}
?>

[mbrown]

array_search may help you, you can pass in an array and check if the values are in the array, if they are it returns you the indexes.

 

<?php
$ipSearch = array('192.168.0.1', '192.168.0.2', '192.168.9.1');
$ipaddresses = array('192.168.0.3', '192.168.0.2', '192.168.1.1', '192.168.9.1');

$found = array_search($ipSearch, $ipaddresses);

if (count($found) > 0) {
    foreach ($found as $key) {
           echo "{$ipaddresses[$key]} was found at index {$key}.<br />";
    }
}
?>

 

so if the ips are in $ipSearch are in $ipaddress?

 

I will be doing it by some ip addresses so certain people can access it off campus but my issue is doing it by subnet at least right now bc some of the subnets are are between 3 and 7 characters xxx.xxx.

 

That is what I am trying to battle right now.

[mbrown]

that code you gave me i get

 

invalid argument supplied for foreach()

[premiso]

array_search may help you, you can pass in an array and check if the values are in the array, if they are it returns you the indexes.

 

 

The above is bad. My internet connection died out so I could not fix it.

 

<?php
$ipSearch = array('192.168.0.1', '192.168.0.2', '192.168.9.1');
$ipaddresses = array('192.168.0.3', '192.168.0.2', '192.168.1.1', '192.168.9.1');

$found = array_intersect($ipSearch, $ipaddresses);

if ($found !== false) {
foreach ($found as $val) {
	echo "{$val} was in both arrays.<br />";
}
}

die();
?>

 

array_intersect_keys should give you the indexes if that is what you are after.

[mbrown]

so i understand this fully, $ipsearch are the ones that you want to test and $ipaddresses are the okay ones so i could do the following

 

 

<?php
$ipaddress = $_SERVER['REMOTE_ADDR'];
$ipSearch = array('$ipaddress');
$ipaddresses = array('192.168.0.3', '192.168.0.2', '192.168.1.1', '192.168.9.1');

$found = array_intersect($ipSearch, $ipaddresses);

if ($found == false) 
{
  echo "You can not access this page based on your IP Address";
}

die();

?>

[/code]