johnwayne77 Posted February 28, 2009 Share Posted February 28, 2009 i'm working on a cron job function i have an orders table with 'date_added' field like this: date_added : 2009-02-28 07:19:33 i want to add two hours to the date_added value... then after i have the date_added+2 hours in a variable i want to perform different tasks.. but that's my main condition.. how do i add two extra hours to a already added date? i managed to add two extra hours to current date.. but that doesn't help.. : echo date("Y-m-d H:i:s", time()+((60*60)*2)); thanks Link to comment https://forums.phpfreaks.com/topic/147310-solved-date/ Share on other sites More sharing options...
premiso Posted February 28, 2009 Share Posted February 28, 2009 MySQL Addtime or MySQL Adddate Not sure which is best, but yea. I would add the 2 hours in mysql and save some php processing time/conversion. Link to comment https://forums.phpfreaks.com/topic/147310-solved-date/#findComment-773250 Share on other sites More sharing options...
johnwayne77 Posted February 28, 2009 Author Share Posted February 28, 2009 i got it: $ago = 2; // ore $timestamp = time() - ($ago * 3600); $final = date("Y-m-d H:i:s", $timestamp); works fine Link to comment https://forums.phpfreaks.com/topic/147310-solved-date/#findComment-773251 Share on other sites More sharing options...
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