nishmgopal Posted March 14, 2009 Share Posted March 14, 2009 Hey Guys I am trying to loop through my table so all the records where job_ID=1 is displayed, so far I have the code below and it only returns the first value: $sql2="SELECT * FROM ID_Table WHERE Job_ID IN (SELECT Job_ID FROM Job_ID WHERE Job_ID=$Job_ID1)"; $result3 = mysql_query($sql2) or die ("Couldn't execute query."); while ($row3=mysql_fetch_array($result3)){ $Skill_ID=$row3['Skill_ID']; $Weight=$row3['Weight']; } So basically I want all the skill_id's and the weights associtated with a particular job_id. Can anyone help? Link to comment https://forums.phpfreaks.com/topic/149377-using-loop/ Share on other sites More sharing options...
RichardRotterdam Posted March 14, 2009 Share Posted March 14, 2009 what does your table(s) look like? Link to comment https://forums.phpfreaks.com/topic/149377-using-loop/#findComment-784521 Share on other sites More sharing options...
hastishah Posted March 14, 2009 Share Posted March 14, 2009 hi just try this $sql2="SELECT * FROM ID_Table WHERE Job_ID IN (SELECT Job_ID FROM Job_ID WHERE Job_ID=$Job_ID1)"; $result3 = mysql_query($sql2) or die ("Couldn't execute query."); while ($row3=mysql_fetch_array($result3)){ $Skill_ID[]=$row3['Skill_ID']; $Weight[]=$row3['Weight']; } Link to comment https://forums.phpfreaks.com/topic/149377-using-loop/#findComment-784522 Share on other sites More sharing options...
nishmgopal Posted March 14, 2009 Author Share Posted March 14, 2009 I tried that code and the return i got was: Array Array Also my tables looks like this: ID_Table: ID Job_ID Skill_ID Weight 1 1 1 4 2 1 2 3 3 1 3 4 4 2 1 5 So what this means is that, the job with Job_ID = 1 has 3 skills (1,2,3) with their weights 4, 3 and 4 respectively. So running my sql should return 1,2,3 with 4,3,4 for job id 1. Link to comment https://forums.phpfreaks.com/topic/149377-using-loop/#findComment-784526 Share on other sites More sharing options...
premiso Posted March 14, 2009 Share Posted March 14, 2009 $sql2="SELECT * FROM ID_Table WHERE Job_ID IN (SELECT Job_ID FROM Job_ID WHERE Job_ID=$Job_ID1)"; $result3 = mysql_query($sql2) or die ("Couldn't execute query."); while ($row3=mysql_fetch_array($result3)){ $Skill_ID[]=$row3['Skill_ID']; $Weight[]=$row3['Weight']; } echo "<pre>"; print_r($Skill_ID); print_r($Weight); echo "</pre>"; echo "The first skill returned is {$Skill_ID[0]}<br />"; echo "The first weight returned is " . $Weight[0] . "<br />"; array I would read up on arrays and their usage, as it is imperative to know how to use them for sql etc. Link to comment https://forums.phpfreaks.com/topic/149377-using-loop/#findComment-784560 Share on other sites More sharing options...
nishmgopal Posted March 14, 2009 Author Share Posted March 14, 2009 Thank you for that. But how can I use that $Skill_ID[] in my next sql statement. Basically now I am trying to pull out the name of the skill based on the Skill_ID, the code is: $sql3="SELECT * FROM Skill_ID WHERE Skill_ID='$Skill_ID[]"; $result4 = mysql_query($sql3) or die ("Couldn't execute query."); while ($row4=mysql_fetch_array($result4)){ but it is not working. All I want to do is, get all the skill id's that any particular job_id is associated with, and then get all the skill names based on all the skill_id's. I thought the best way for this was to have multiple sql statemens with stored varibles? Link to comment https://forums.phpfreaks.com/topic/149377-using-loop/#findComment-784580 Share on other sites More sharing options...
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