PHP math explanation

[zavin]

Most of my site I wrote and so I know how and why ot works. Some of the stuff on my site a gathered from other sources. I have to know what every thing does so I'm hoping someone can explain in detail exactly how the following math works. If someone could use an example to explain I would appreciate it. Thanks in advance for any help provided.

[shlumph]

Sure

[zavin]

lol I guess it would help if I included the code I am referring to. Didn't notice it was missing until shlumph's post.

function Get_The_Level($exp) {
  $a=0;
  $end =0;
  for($x=1; ($end==0 && $x<100); $x++) {
    $a += floor($x+1500*pow(4, ($x/7)));
    if ($exp >= floor($a/4)){
} else {
  return $x;
  $end=1;
}
  }

[shlumph]

LOL what on earth is this function used for?

[zavin]

An rpg game. It returns the level of a character based on the amount of experience. The experience is a number from a DB. 

[corbin]

Well, it's already fairly straightforward, so I don't know what you want someone to explain....

 

Perhaps translate it to more math-ish terms?

 

for variables a = 0, b = 0, x = 1:

 

while end is 0 and x is less than 100:

a += greatest integer value of $x+1500*4^($x/7)

if(exp < greatest integer value of a/4)

    exit the function and return x.

 

 

 

By the way, the PHP code is not optimized.

 

function Get_The_Level($exp) {
$a=0;
for($x=1; $x < 100; ++$x) {
	$a += floor($x+1500*pow(4, ($x/7)));
	if($exp < floor($a/4)){
		return $x;
	}
}
}

 

 

[GingerRobot]

Also it's entirely pointless doing anything with variables (or, indeed, anything at all) after returning from a function. The code is entirely unreachable - the program counter's already been returned to the caller and all the local variables of the function have been popped from the stack.

 

So setting $end to 1 here is never ever ever executed:

 

     return $x;
     $end=1;