[SOLVED] Checking if website is real

[Spike121]

Okay, so I know this should be possible, and I haven't tried it yet, but I don't know.

 

What I want to do is let a user enter a website link, then I want the code to try to connect to the website, to see if it's real. I know it's possible if you're using the actually IP addresses of websites, but I don't know if I need the IP addresses, or if somehow the code can find them, and then check?

 

Appreciate the help 

 

I will update the post if/when I can find my old code of check the IP addresses

 

Edit: Okay, so I've found this:

@fsockopen($serverip, $serverport, &$errno, &$errstr, 10)

Not sure if it will work, I'll test it now. However, what port would be used? I remember FTP port is 21 or 22, but I doubt it would be those ports. Maybe port 80?

[Maq]

I've seen posts in these forums about this but here's a tutorial I found in 2 seconds with Google that looks promising:

 

Check If URL Exists

[Spike121]

Hmm, does look promising. Guess you need to know what to search  . I was looking for about half an hour. Thank you! I'll test it now.

[Spike121]

Okay, so I tried this...

 

<?php 
$url = "http://www.google.com";
	  	function test_url_file($url) {
		$res = (($ftest = @fopen($url, ‘r’)) === false) ? false : @fclose($ftest);
		return ($res == TRUE) ? 1:0 ;
		} 
		if ($res = 1) {
		echo "Connected.";
		} else {
		echo "WRONG.";
		}
		?>

 

And the page returned "Connected.", and I was happy. So I tried a different one, obviously not a website (I typed in random words, with spaces, which is impossible for a website to have), and it still said connected. I'm not sure if I did it right, I'm not very good with functions yet, or ftests (which I think are socket tests but I'm probably wrong, still learning).

 

Any ideas? Should I try the other method on that page?

[Maq]

Change this line to:

 

         if ($res == 1) {

[Spike121]

Now it shows everything as "WRONG". Should I change it to

else if ($res == 0) { 
echo "WRONG";
}

 

Edit: Wait, that wouldn't matter. I'm trying it with all variations of google.com. http://google.com. http://www.google.com. www.google.com. None work.

[Maq]

You're supposed to get the value that's returned from the function.

 

Try this.

 

function test_url_file($url) {
   $res = (($ftest = @fopen($url, 'r')) === false) ? false : @fclose($ftest);
   return ($res == TRUE) ? 1:0;
} 

$url = "http://www.google.com";
echo (test_url_file($url)) == 1 ? "Connected" : "Not Connected";
?>

[Spike121]

Perfect, works good. However, I don't quite understand that last line,

echo (test_url_file($url)) == 1 ? "Connected" : "Not Connected";

 

That's obviously where it's returning the words if it's connected or not, but what if I want it to display a huge amount of code, instead of one or two words? Would I just do...

 

<?php 

$url = "http://google.com";

   function test_url_file($url) {
   $res = (($ftest = @fopen($url, 'r')) === false) ? false : @fclose($ftest);
   return ($res == TRUE) ? 1:0;
} 

echo (test_url_file($url)) == 1 ? " ?> // End PHP here to write lots of lines of code
//This is
//lots of
//lines of code
<?php " : "?>
//more code
//
//
<?php ";
?>

[Maq]

This line (called a "ternary operator"):

 

echo (test_url_file($url)) == 1 ? "Connected" : "Not Connected";

 

Translates to:

 

if(test_url_file($url) == 1) {
   echo "Connected";
} else {
   echo "Not Connected";
}

 

As you can see it saves a lot of room when writing code, but in your case if you want to write and execute more code you have to use if/else statements.

[Spike121]

Thank you very much