iPixel Posted April 16, 2009 Share Posted April 16, 2009 So im starting to have the need to use AJAX. And i know it will come of great use to me. However i have ZERO clue how to get started. What i need to do : I have a text box - name = searchPPL. I have a hidden div layer - name = DIRpop. what i want to learn how to do is, do a name search against a MySQL db. onKeyUp with each letter entered i would like for the value of the textbox be passed via javascript i assume into a file called suggestor.php which will then use the value passed to query the database and return the result to the javascript i guess so that i can use innerHTML = "result of mysql db goes here". If anyone can help me out or point me in the right direction or a good site with a good example i'd greatly appreciate it. Thanks to all who help. Quote Link to comment https://forums.phpfreaks.com/topic/154366-complete-ajax-noob-phpajax-query-db/ Share on other sites More sharing options...
Zane Posted April 16, 2009 Share Posted April 16, 2009 google "AJAX tutorial" http://www.google.com/search?q=AJAX+tutorial&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a The top results # AJAX Tutorial · Internet Free HTML XHTML CSS JavaScript DHTML XML DOM XSL XSLT RSS AJAX ASP ADO PHP SQL tutorials, references, examples for web building. www.w3schools.com/Ajax/Default.Asp - 23k - Cached - Similar pages - Intro Example Database ResponseXML XML File Server Script Source Browsers More results from w3schools.com » # Ajax Tutorial · Web Development - 2 visits - 12/18/08 AJAX, the standard to build dynamic websites. How to build an AJAX page with examples. XMLHttpRequest methods and attributes. www.xul.fr/en-xml-ajax.html - 28k - Cached - Similar pages - # Ajax Tutorial - Tutorial · Web Development This tutorial will introduce you to the basics of Ajax and show you how to send and receive data from a server without using a "Submit" button approach. ... www.tizag.com/ajaxTutorial/ - 12k - Cached - Similar pages - Quote Link to comment https://forums.phpfreaks.com/topic/154366-complete-ajax-noob-phpajax-query-db/#findComment-811577 Share on other sites More sharing options...
iPixel Posted April 16, 2009 Author Share Posted April 16, 2009 Ok i got it working to a point. I need just a bit of help understanding why something is happening. Got script from http://www.tizag.com/ajaxTutorial/ajax-javascript.php My form >> <form action="" method="get" name="searchBOX"> <td align="left"> <input type="text" id="searchPPL" name="searchPPL" class="login_txt_box" autocomplete="off" onkeyup="showSuggestion(this.value)" onblur="hideSuggestion()" /> <input type="submit" value="Search" name="submit" id="submit" class="search_btn" onmouseover="CCon(this)" onmouseout="CCoff(this)" /> </td> </form> My Javascript >> function showSuggestion(myvalue) { document.getElementById("DIRpop").style.visibility = 'visible'; ajaxFunction(myvalue); } function hideSuggestion() { document.getElementById("DIRpop").style.visibility = 'hidden'; } function ajaxFunction(q) { //alert(q); var ajaxRequest; // The variable that makes Ajax possible! try{ // Opera 8.0+, Firefox, Safari ajaxRequest = new XMLHttpRequest(); } catch (e){ // Internet Explorer Browsers try{ ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try{ ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e){ // Something went wrong alert("Your browser broke!"); return false; } } } // Create a function that will receive data sent from the server ajaxRequest.onreadystatechange = function() { if(ajaxRequest.readyState == 4) { var ajaxDisplay = document.getElementById('DIRpop'); ajaxDisplay.innerHTML = ajaxRequest.responseText; } } ajaxRequest.open("GET", "../suggestor.php?q=" + q, true); ajaxRequest.send(null); } My Php code >> $q = mysql_real_escape_string($_GET["q"]); $SP_query = "SELECT * FROM syx_ad WHERE firstname LIKE '%$q%' OR lastname LIKE '%$q%'"; $SP_sql = mysql_query($SP_query) or die(mysql_error()); $display_string = ""; do { $display_string.= $SP_result['firstname'] . " " . $SP_result['lastname'] . "<br />"; } while($SP_result = mysql_fetch_assoc($SP_sql)); echo $display_string; This works about 90%, although it has it's glitches, and im curious to understand why. Let's use the name Jhonny Bravo as out test subject. As i start to type J h o n n y ... everything works great but when i get to the space and start typing up the last name Jhonny B... the div layer no longer displays the names and just goes empty. Any clue why ? Quote Link to comment https://forums.phpfreaks.com/topic/154366-complete-ajax-noob-phpajax-query-db/#findComment-811648 Share on other sites More sharing options...
jackpf Posted April 16, 2009 Share Posted April 16, 2009 Are you encoding/decoding your GETS/POSTS? Quote Link to comment https://forums.phpfreaks.com/topic/154366-complete-ajax-noob-phpajax-query-db/#findComment-811731 Share on other sites More sharing options...
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