preg_match_all Questions

[JustinK101]

I am trying to do a preg_match_all and return any array of the items found.

 

Here is the pattern I am looking for:

 

id="{wildcard}@domain.com"

 

Here is the code I have:

 

$results = array();
preg_match_all('/id=\"*\@domain.com\"/', $html, $results);
print_r($result);

 

The output is: Array ( [0] => Array ( ) )

 

Does that mean it found a match, but how come the text is empty?

[premiso]

<?php
$html = "&id=test@test.com  some extra stuff \n and id=teststst@test.com and eve some more \n stuff";
$results = array();
preg_match_all('~id=(.*?) ~', $html, $results);
echo "<pre>";
print_r($results);
die();
?>

 

Since you did not provide us with an example of what you want to parse, this will have to suffice, it requires that there be a space after the @domain.com to fetch the data.

 

Output of the above:

Array
(
    [0] => Array
        (
            [0] => id=test@test.com 
            [1] => id=teststst@test.com 
        )

    [1] => Array
        (
            [0] => test@test.com
            [1] => teststst@test.com
        )

)

[JustinK101]

So is there a way to not require a space? Basically here is a context example of code:

 

<td class="cell truncate" truncate="80" id="justin@domain.com">justin@domain.com</td>

 

I am looking for id="{wildcard}@domain.com" should return: id="justin@domain.com" right?

[premiso]

<?php
$html = '&id="test@test.com"  some extra stuff \n and id="teststst@test.com" and eve some more \n stuff';
$results = array();
preg_match_all('~id="(.*?)"~', $html, $results);
echo "<pre>";
print_r($results);
die();
?>

 

Output:

Array
(
    [0] => Array
        (
            [0] => id="test@test.com"
            [1] => id="teststst@test.com"
        )

    [1] => Array
        (
            [0] => test@test.com
            [1] => teststst@test.com
        )

)

[JustinK101]

Premiso:

 

Close, but I don't think the regular expression is looking for @domain.com.

[premiso]

Premiso:

 

Close, but I don't think the regular expression is looking for @domain.com.

 

Misundestanding. I thought, when you said @domain.com it was a reference.

 

<?php
$html = '&id="test@domain.com"  some extra stuff \n test89@domain.com and id="teststst@domain.com" and id="test2@domain.com" and eve some more \n and id="test3@domain.com" stuff';
$results = array();
preg_match_all('~id="(.*?)@domain.com"~s', $html, $results);
echo "<pre>";
print_r($results);
die();
?>

 

Output:

Array
(
    [0] => Array
        (
            [0] => id="test@domain.com"
            [1] => id="teststst@domain.com"
            [2] => id="test2@domain.com"
            [3] => id="test3@domain.com"
        )

    [1] => Array
        (
            [0] => test
            [1] => teststst
            [2] => test2
            [3] => test3
        )

)

[nrg_alpha]

$html = '&id="test@domain-x.com"  some extra stuff \n and id="teststst@domain.com" and eve some more \n stuff id="whatever"... &id="blah@domain.com"';
preg_match_all('#id="([^"]+@domain.com)"#', $html, $matches);
echo "<pre>".print_r($matches[1], true);

 

Output:

Array
(
    [0] => teststst@domain.com
    [1] => blah@domain.com
)

 

This assumes of course, that you absolutely want ...@domain.com (change this to match the actual domain in question of course). In order to ensure that I capture the domain and not some stuff in some id=".." that is not related, I use a negated character class..[^"]+ So the idea is to sacrifice speed for more accuracy.