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[SOLVED] "If" Issues


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Can't seem to get

if($x && $m){

if($x &! $y)

to work, any help would be appreciated. This code uses a radio button and a text box for the numbers to add to the variables...

 

if($_POST['option']){
$opts = $_POST['option'];
foreach ($opts as $o) {
if($o == 1){
if($y &! $x){
if($y &! $m){$page1=1;
echo "You lost " . $z . " Dollars.<br />";}}
if($x &! $y){
if($x &! $m){$page1=1;
echo "You lost " . $d . " Euros.<br />";}}
if($x && $y){
if($x &! $m){$page1=1;
echo "You lost " . $zz . " Pence.<br />";}}
if($x && $m){
if($x &! $y){$page1=1;
echo "You lost " . $d . " Francs.<br />";}}}
if($x && $y && $m){$page1=1;
echo "You lost " . $zzz . " Yen.<br />";}}

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PHP Code Page (with other code)

$y = $_REQUEST['y'];
$x = $_REQUEST['z'];
$m = $_REQUEST['m'];

Main Page that sends the request to the code page.

<input name="z" type="text" /><br>
<input name="y" type="text" /><br>
<input name="m" type="text" /><br>

Mind you this is a test, so variable names mean nothing right now...

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here u forgot a bracket to end the first if statment

<?php
if($_POST['option']){
$opts = $_POST['option'];
foreach ($opts as $o) {
	if($o == 1){
		if($y &! $x){
			if($y &! $m){
				$page1=1;
				echo "You lost " . $z . " Dollars.<br />";
			}
		}
		if($x &! $y){
			if($x &! $m){
				$page1=1;
				echo "You lost " . $d . " Euros.<br />";
			}
		}
		if($x && $y){
			if($x &! $m){
				$page1=1;
				echo "You lost " . $zz . " Pence.<br />";
			}
		}
		if($x && $m){
			if($x &! $y){
				$page1=1;
				echo "You lost " . $d . " Francs.<br />";
			}
		}
	}
	if($x && $y && $m){
		$page1=1;
		echo "You lost " . $zzz . " Yen.<br />";
	}
}
}
?>

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&! works just the same as && !(var)

 

After some work on it, I discovered that $m had to be in front for the rest of it to function.

 

if($m && $y){
if($m &! $x){$page1=1;
echo "You lost " . $zz . " Pence.<br />";}}
if($m && $x){
if($m &! $y){$page1=1;
echo "You lost " . $d . " Francs.<br />";}}

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Share on other sites

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