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Hi

 

My strongest point is just not REGEX! Im trying to return a string that is between {sls}Content to return here{/sle} 

 

So basically {sls} must be at the beginning, and {/sle} at the end and return the "Content to return here" bit

 

how would i do this? Iv tried:

 

preg_match ( '/^({sls})({/sle})$/', $string, $array );

 

but get the following error:

 

 

Warning: preg_match() [function.preg-match]: Unknown modifier 'l' in /home/clients/public_html/cms/application/Engine/plugins/function.admin_list_sections.php on line 26

 

cheers

 

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I cant tell if that is a pipe or an l between ss and se.

If not

<?php
$subject = "{sls}Content to return here{/sle}";
if(preg_match('%{sls}(.*){/sle}%', $subject, $regs)) {
print $regs[0];
}
?>

 

If it is a pipe

<?php
$subject = "{s|s}Content to return here{/s|e}";
if(preg_match('%{s\\|s}(.*){/s\\|e}%', $subject, $regs)) {
print $regs[0];
}
?>

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oh it does work. thopugh only if its text.

 

i want it to do this on HTML code but when i use HTML as the subject like the exmaple below, the array of items is empty:

 

<table>
    {sle}
        <tr>
            <td>TEST</td>
        </tr>
    {/sle}
</table>

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Iv tried {sls}(.*}{/sle}  and the array comes back empty!

That's not a valid regex, you tried to close a ( with a }? Close the ( with a )

 

  what are the % for?

You need to use the same (unique) character for the first and last place, % is unlikely to be used in the rest of the regex.

 

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can you tell me what the % and %s are for i thought with preg_match you have to start and end the expression with /

They're delimiters. It just means it holds a regex expression. Without them, it would match just a string, but if you want to match strings, go with strpos or strstr.

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if(preg_match('%{sls}(.*){/sle}%s', $subject, $regs)) {

 

In general, it is frowned upon to use .* or .+ This thread explains why (post #11 and 14 - In other words, potential speed / accuracy issues).

So I would make it a lazy quantifier...

 

can you tell me what the % and %s are for i thought with preg_match you have to start and end the expression with /

They're delimiters. It just means it holds a regex expression. Without them, it would match just a string, but if you want to match strings, go with strpos or strstr.

 

Actually, without delimiters, you would get warnings (unless it just so happens that the first and last character within the quoted pattern (modifiers aside) is a viable delimiter / delimiter set - in which case the regex engine would then treat as delimiters), which in turn might not generate an error or warning, but you won't get the results you are looking for.

 

A typical pitfall example:

 

preg_match('<img src="([^"]+)" />', $str, $match);

 

This is legal (only because the first and last character form a legit delimiter set.. so the delimiters are < and >, thus the pattern only looks for img src=... when the person in question might want to include the < and > characters.

Without any form of delimiters, you'd get warnings.

 

 

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Was just a quick example

if(preg_match('%{sls}(.*){/sle}%s', $subject, $regs)) {

 

How do you suggest rewriting to match absolutely anything inside the capture group?

 

That doesn't sound quite right... everything the dot_match_all can get will be stored into the capture..

By this you mean matching only between {sls} and {/sle}? By making it lazy through the addition of the ? after .*

 

if(preg_match('%{sls}(.*?){/sle}%s', $subject, $regs)) {

 

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