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Problem with images


Sorrow

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Hi, here is my problem. I have to display 3 cd case with the movie title underneath and they have to be side by side. And with what I have I can only put them one on top of the other .

<tr>
      <td colspan="2">
         
           
         <?php

include 'opendb.php';

$query  = "SELECT * FROM Trailers Order by T_index DESC LIMIT 0,3 ";
$result = mysql_query($query);

while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
    echo "<a STYLE='text-decoration:none' href='/b2.php?index={$row['T_index']}'><img src='{$row['T_Case']}' width='60' height='80' border = '0'>";
    echo "<font size = '2'>{$row['T_Title']}</font></a>";
   
}
mysql_close($con);

?>

</td>

 

This is what I need to have done:

 

 

              _____          _____          _____

              |      |        |        |      |        |

              |      |        |        |      |        |

              -----          ------        ------

              Title            Title            Title

 

 

Thank you

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To make anything side-by-side in a table, use <td> without closing </tr>. This one is side-by-side:

 echo "<a STYLE='text-decoration:none' href='/b2.php?index={$row['T_index']}'></td><td><img src='{$row['T_Case']}' width='60' height='80' border = '0'></td>";
    echo "<td><font size = '2'>{$row['T_Title']}</font></a></td></tr>";

And from your example with the title underneath:

 echo "<a STYLE='text-decoration:none' href='/b2.php?index={$row['T_index']}'></td><td><img src='{$row['T_Case']}' width='60' height='80' border = '0'></td></tr>";
    echo "<tr><td><font size = '2'>{$row['T_Title']}</font></a></td></tr>";

 

 

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Why is everyone posting parsing php? Is it difficult to understand that php has absolutely no effect on the final rendering? HTML/CSS class 101 lesson 1. PHP is serverside. HTML is clientside. Which one affects final rendering picture: html.

I was waiting for someone to point this out. ;)

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