[SOLVED] Odd/Even

[947740]

How would I go about determining if a number is odd or even?

 

Is there an easier way than this:

if ($i % 2) {
echo "$i is odd";
} else {
echo "$i is even";
}

[T0Rtur3]

hmm didn't see that you changed your post. Not that I know of

[papaface]

$i = 10;
if ( $i&1 )
{
echo "$i is odd";
}
else
{
echo "$i is even";
}

[947740]

$i = 10;
if ( $i&1 )
{
echo "$i is odd";
}
else
{
echo "$i is even";
}

 

Nice.

http://newsourcemedia.com/blog/php-how-to-find-odd-and-even-numbers/

 

Thanks for the help.

[papaface]

$i = 10;
if ( $i&1 )
{
echo "$i is odd";
}
else
{
echo "$i is even";
}

 

Nice.

http://newsourcemedia.com/blog/php-how-to-find-odd-and-even-numbers/

 

Thanks for the help.

If you used google in the first instance you would have saved everyones time...

[Maq]

The only other thing you can do is convert it into ternary to only make it one line.  Other than that, there is no native function, if that's what you're asking.

[947740]

The only other thing you can do is convert it into ternary to only make it one line.  Other than that, there is no native function, if that's what you're asking.

 

Okay.  Thanks.

[PFMaBiSmAd]

It depends on what you mean by simpler and how you are using the logic in your code -

echo ($i % 2) ? "$i is odd" : "$i is even";

echo ($i & 1) ? "$i is odd" : "$i is even";

[Maq]

The only other thing you can do is convert it into ternary to only make it one line.  Other than that, there is no native function, if that's what you're asking.

 

Okay.  Thanks.

 

Sure, if you wanted to do this, then follow PFMaBiSmAd's post.