arguments in a function shothand...

[asmith]

Hi,

 

How do you pass optional parameters for a function.

for example :

 

I want to pass 2 arguments and the 3rd is optional :

 

myfunction ($a, $b[, $c]);  // if $c is set, send it

 

I typed it like php explanation of functions. But apparently it gives me a parsing error.

 

 

[Richard]

To make the third (final) argument optional you could give it a default value, for example;

 

<?php
myfunction($a, $b, $c = '')
{

}

[asmith]

Yea sure. I meant not sending at all.

nvm, I wanted to know if there's any syntax for it.

[Richard]

Have a look at;

func_num_args()

func_get_arg()

func_get_args()

[asmith]

Thanks for the effort mate.

 

I meant SENDING parameters to a function(Using it), Not the syntax in the function structure.

[Mark Baker]

myfunction($a, $b, $c = '')
{
   return $a.' '.$b.' '.$c.'<br />';
}

echo myfunction(1,2,3);

echo myfunction(1,2);

[asmith]

lol I'm very very very sorry guys for this stupid question.

 

How do you write it with the if statement?

for example :

 

echo myfunction(1,2, (if 2 ==2?  5 : don't send anything));

 

In other words, the shorthand of this :

 

if (2 == 2)

    echo myfunction(1,2,5);

else

    echo myfunction(1,2);