[SOLVED] search a folder for highest number file name

[jasonc]

i have a folder with many files in it all numbered with dates.

 

i.e. 20090701

which would be (1 July 2009)

 

each file is a HTML file

 

20090701.html

 

and i wish to find the most up-to-date file in this folder.

 

i have this so far but thought i'd try to use a mask but this did not work

Code:

 

<?

$maxfile = max(scandir($uploaddir . "articles/*.htm"));

echo("'" . $maxfile . "'");

?>

 

reason being is that their are some other files also in this folder but i only want to have the files with .htm as the ext and not all the other files to be used in the list.

 

how do i stop the other files from being in this list ?

 

 

 

 

EDITED....

 

 

 

$maxfile = max(glob("articles/*.htm"));

echo("'" . $maxfile . "'<br><br>");

 

 

preg_match('{(\d+-\d+-\d+)}', $maxfile, $m);  IS THIS THE CORRECT WAY TO GRAB THE NUMVERS WITH THE - BETWEEN THEM ?

 

 

echo $m[1];

[kenrbnsn]

You should use the glob function.

 

<?php
$files = glob($uploaddir . 'articles/*.htm');
$maxfile = $files[count($files) - 1];
echo $maxfile;
?>

 

Ken

[jasonc]

yes this seems to work..  but how would i correctly grab the numbers from the file name?

[kenrbnsn]

I would use pathinfo

<?php
$files = glob($uploaddir . 'articles/*.htm');
$maxfile = $files[count($files) - 1];
echo $maxfile . '<br>';
$dt = pathinfo[$maxfile,PATHINFO_FILENAME];
echo date('Y-m-d',strtotime($dt));
?>

 

Ken

[jasonc]

I would use pathinfo

<?php
$files = glob($uploaddir . 'articles/*.htm');
$maxfile = $files[count($files) - 1];
echo $maxfile . '<br>';
$dt = pathinfo[$maxfile,PATHINFO_FILENAME];
echo date('Y-m-d',strtotime($dt));
?>

 

Ken

 

i get the following error...

 

Parse error: syntax error, unexpected '['  in the $dt = pathinfo[$maxfile,PATHINFO_FILENAME];  line

[johnathanhebert]

You could just use the basename() function...

 

echo basename($maxfile,".htm");

[jasonc]

thank you to all that have helped