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[SOLVED] Shorten/simplify code


soycharliente

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I used to have this code as independent functions for each year (so I would have 4 right now had I continued to do it that way). I thought that I could write it so that it would just update itself and I wouldn't have to keep adding functions.

 

This is what I have, but I feel like it's super roundabout and maybe a bit overkill. Am I just being dumb or is there a simpler way to do this?

 

I have a table with some data. I want to display the data for each year ago, that data exists, since today.

<h3>This day (<?php echo $today = date('F d'); ?>) years ago</h3>
<?php
$i = floor((date('U') - date('U',strtotime(firstLunch()))) / (60*60*24*7*52));
$count = 0;
while ($count <= $i)
{
$ago = date("Y-m-d", strtotime("-{$count} year"));
$year = date('l, Y', strtotime($ago));
$sql = "SELECT el.`loc`,dee.`pid`,dee.`rating`,dee.`thedate`
			FROM `lunch_locations` el
			JOIN `lunch_data` dee ON el.`id`=dee.`pid`
			WHERE `thedate`='{$ago}'";
$result = mysql_query($sql) OR DIE ("/Stats Error #5.");
$rows = mysql_num_rows($result);
if ($rows > 0)
{
	$r = mysql_fetch_assoc($result);
	$loc = $r['loc'];
	$rating = (empty($r['rating'])) ? "no rating" : "a rating of {$r['rating']}";
	echo "{$year} : {$loc} with {$rating}.";
}
else { echo "{$year} : Must not have been a workday."; }
if ($count<=$i) { echo '<br />'; }
$count++;
}
dbclose();
?>

 

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Would something like this work?

SELECT el.`loc`,dee.`pid`,dee.`rating`,dee.`thedate`
            FROM `lunch_locations` el
            JOIN `lunch_data` dee ON el.`id`=dee.`pid`
            WHERE MONTH(`thedate`)= MONTH(CURDATE())
            AND DAY(`thedate`) = DAY(CURDATE())

 

SELECT ... WHERE ... (the Month and Day matches the current Month and Day) ?

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TABLE `lunch_data` (
  `id` int( NOT NULL auto_increment,
  `pid` int(4) NOT NULL default '0',
  `thedate` date NOT NULL default '0000-00-00',
  `rating` int(4) default NULL,
  `spent` float default NULL,
  `comment` text,
  `publish` datetime NOT NULL,
  PRIMARY KEY  (`id`),
  UNIQUE KEY `thedate` (`thedate`)
)

 

TABLE `lunch_locations` (
  `id` int(4) NOT NULL auto_increment,
  `loc` varchar(255) NOT NULL default '',
  `menu` text,
  `map` text,
  `tally` int( NOT NULL default '0',
  PRIMARY KEY  (`id`),
  UNIQUE KEY `loc` (`loc`)
)

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Would something like this work?

SELECT el.`loc`,dee.`pid`,dee.`rating`,dee.`thedate`
            FROM `lunch_locations` el
            JOIN `lunch_data` dee ON el.`id`=dee.`pid`
            WHERE MONTH(`thedate`)= MONTH(CURDATE())
            AND DAY(`thedate`) = DAY(CURDATE())

 

SELECT ... WHERE ... (the Month and Day matches the current Month and Day) ?

 

In theory this def seems to be the way to go. Maybe add an OR statement to get all the years I want. Then I have all the results in 1 simple query.

 

BRB for this one.

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Ok. This statements works great and cuts down A LOT of the PHP, except I wanted to be able to echo statements saying there wasn't data for that year. I can't return a result for a year that doesn't have data, so it makes it difficult to echo something out this way.

 

SELECT el.`loc`,dee.`pid`,dee.`rating`,dee.`thedate` FROM `lunch_locations` el
JOIN `lunch_data` dee ON el.`id`=dee.`pid`
WHERE MONTH(`thedate`)=MONTH(CURDATE()) AND DAY(`thedate`)=DAY(CURDATE())
AND (YEAR(`thedate`)>='2005' OR YEAR(`thedate`)>=YEAR(CURDATE()))

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What happens when change JOIN to LEFT JOIN or RIGHT JOIN in the query?  This is not my strong point, but if I remember correctly, one of those will retrieve null values as well.

 

(only modified the last part for BETWEEN

SELECT el.`loc`,dee.`pid`,dee.`rating`,dee.`thedate` FROM `lunch_locations` el
JOIN `lunch_data` dee ON el.`id`=dee.`pid`
WHERE MONTH(`thedate`)=MONTH(CURDATE()) 
  AND DAY(`thedate`)=DAY(CURDATE())
  AND ( YEAR(`thedate`) BETWEEN 2005 AND YEAR(CURDATE()) )

 

(edit: also I'm not sure which ordering of the AND statements would be more efficient)

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