Help with Blocking url

[dunnsearch]

Right I have the following:

if (in_array($URL1, $URL2, $URL3)) {} else {

 

How would i reaplace those URL's with URL4?

Thanks. I need this badly

[pudge1]

<?php
str_replace($url1,$url4,$text);
str_replace($url2,$url4,$text);
...
?>

 

Is that what you mean?

[corbin]

Huh?

 

 

I think you should read the manual page on in_array.

[dunnsearch]

Ok here is is:

$torrenthost = $torrenthost[0]; // torrent host name

$torrenthostlink = $torrenthostlink[0]; // torrent download link

$torrentnameinhost = $torrentnameinhost[0]; // torrent name in host

$torrentupdateinhost = $torrentupdateinhost[0]; // torrent update time

$blockedsites = array("test.com", "www.anothertest.com", "www.example.com", "url.com", "www.phpfreaksexample.com");

if (in_array($torrenthost, $torrenthostlink, $blockedsites)) {} else {

 

How can i replace them with another url if theye should up on page

 

What to put in?

if (in_array($torrenthost, $torrenthostlink, $blockedsites)) {} else {

???

[mikesta707]

you aren't using the in_array() function correctly... at all...

[dunnsearch]

so how do i get it to replace the blocked urls?

[mikesta707]

what do you mean by replace the blocked URL? replace them with what?

[dunnsearch]

Just to block it from appearing. You see. I have created a meta search engine but it also picks up adverts from the search engines it searches. I need to remove these links from the files list. So just to block it from appearing on my site will do

[Monadoxin]

If the page contents is inside a string what you could do is create an array with all of the bad urls that you do not want in your page, then do a loop through that array. In the loop see if the page contains the 'bad site' and replace it with whatever else you want:

 

<?php
$sPageContent = "blah blah blah, look at this website: http://badurl2.com!";
$aBadSites = array("http://badurl1.com", "http://badurl2.com", "http://badurl3.com", etc);

foreach($aBadSites as $sBadSite) {
$sPageContent = str_replace($sBadSite, "http://goodsite.com", $sPageContent);
}

print $sPageContent;
?>

 

The output would be this:

 

blah blah blah, look at this website: http://goodsite.com!