gotornot Posted September 18, 2009 Share Posted September 18, 2009 Im trying to run a simple if command and this doesnt seem to work im trying to get it to hiighlight the option already selected in the db any ideas why? function selected() { global $selectedno; //for loop to loop through 10 $a = 11; for ($i = 0; $i <10; $i++) { $a = --$a; $num = $a; if ($selectedno == $num) { $bash = ' selected="selected"'; } echo '<option value="' . $a . '"' . $bash . '>' . $a . ' ' . $selectedno . ' </option>'; } } Quote Link to comment https://forums.phpfreaks.com/topic/174695-i-cant-get-it-to-output/ Share on other sites More sharing options...
Maq Posted September 18, 2009 Share Posted September 18, 2009 1) Use code tags. 2) Why are you declaring '$selectedno' global? I don't see where that variable is coming from. If it's being read from the DB previously in the script then you should just pass it to the function as a parameter. 3) In your echo statement, you can use double quotes for the string and single quotes for the attributes so you don't have to keep concatenating to the string by breaking out of it. Quote Link to comment https://forums.phpfreaks.com/topic/174695-i-cant-get-it-to-output/#findComment-920685 Share on other sites More sharing options...
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