[SOLVED] rand (1000, 1025)(2000,2025)(3000,3025)

[markvaughn2006]

On the rand() function is there a way to have it pick a random number between say... 1000-1025 AND 2000-2025 AND 3000-3025, etc... so possible outcomes could be 2014, 1023, 1005, 3002, etc... all from this one rand()

 

I know thats weird , just have a specific reason for wanting to do this... Thanks in advance!!

[salathe]

From one call to rand(), no.

[Daniel0]

I suppose you could always do like this:

 

$rand = array(rand(1000,1025), rand(2000,2025), rand(3000,3025));
$num = $rand[rand(0,2)];

 

Edit: Or like this:

$first = rand(1,3) * 1000;
$num = rand($first, $first + 25);

[Adam]

As salathe said there isn't with a single call to rand(), but you could use something like:

 

$ranges = array(
    0 => array(1000, 1025),
    1 => array(2000, 2025),
    2 => array(3000, 3025)
);

$n = array_rand($ranges);

echo rand($ranges[$n][0], $ranges[$n][1]);

[Psycho]

I'll throw in another solution:

 

$values = array_merge(range(1000, 1025), range(2000, 2025), range(3000, 3025));
$rand_value = $values[array_rand($values)];

 

EDIT: MrAdam went with a similar solution, but mine picks a single random value out of the entire list instead of first selecting one of three lists and then selecting a value out of that.

[markvaughn2006]

cool thanks, that'll work!!