FutonGuy Posted December 31, 2009 Share Posted December 31, 2009 Hi, I am having problem solving my query error, would appreciate if someone can assist me. $val_d = $_GET['val_d']; $sql = "SELECT * FROM device"; $sql .="WHERE device_num LIKE '%$val_d%' "; the error code i had was: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LIKE '%" . urlencode($val_d) . "%'' at line 2" There is no problem if my query is $sql = "SELECT * FROM device WHERE device_num LIKE '%$val_d%' "; I did the 1st method is because i need it in my later script. Appreciate if someone can assist me and guide me along. Cheers Quote Link to comment https://forums.phpfreaks.com/topic/186757-need-help-on-a-query-issue/ Share on other sites More sharing options...
premiso Posted December 31, 2009 Share Posted December 31, 2009 The error you provided does not match your code. As it seems you are trying to include a urlencoded string, but you forgot to exit out of the current string. As for the first statement, you need a space before the WHERE or after the FROM device for that to work properly. But yea, show us the proper code to solve your issue. Quote Link to comment https://forums.phpfreaks.com/topic/186757-need-help-on-a-query-issue/#findComment-986231 Share on other sites More sharing options...
FutonGuy Posted December 31, 2009 Author Share Posted December 31, 2009 $_GET['val_d'] is an input that came from another php file. This code here is to allow user to save the results which is shown on the web browser. So when user clicked on [save result], $_GET['val_d'] will pass the value to this code here. Here's my code: $val_d = $_GET['val_d']; $sql = "SELECT * FROM device"; $sql .="WHERE device_num LIKE '%$val_d%' "; $results = mysql_query($sql) or die (mysql_error()); $count = mysql_num_fields($results); for ($i = 0; $i < $count; $i++){ $header .= mysql_field_name($results, $i)."\t"; } while($row = mysql_fetch_row($results)){ $line = ''; foreach($row as $value){ if(!isset($value) || $value == ""){ $value = "\t"; }else{ # important to escape any quotes to preserve them in the data. $value = str_replace('"', '""', $value); # needed to encapsulate data in quotes because some data might be multi line. # the good news is that numbers remain numbers in Excel even though quoted. $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim($line)."\n"; } # this line is needed because returns embedded in the data have "\r" # and this looks like a "box character" in Excel $data = str_replace("\r", "", $data); # Nice to let someone know that the search came up empty. # Otherwise only the column name headers will be output to Excel. if ($data == "") { $data = "\nno matching records found\n"; } # This line will stream the file to the user rather than spray it across the screen header("Content-type: application/octet-stream"); # replace excelfile.xls with whatever you want the filename to default to header("Content-Disposition: attachment; filename=excelfile.xls"); header("Pragma: no-cache"); header("Expires: 0"); echo $header."\n".$data; Quote Link to comment https://forums.phpfreaks.com/topic/186757-need-help-on-a-query-issue/#findComment-986232 Share on other sites More sharing options...
FutonGuy Posted December 31, 2009 Author Share Posted December 31, 2009 Issue solved! cheers Quote Link to comment https://forums.phpfreaks.com/topic/186757-need-help-on-a-query-issue/#findComment-986261 Share on other sites More sharing options...
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