if bigger than 100

[dachshund]

hi,

 

i'm trying to determine if $rows['views'] is bigger than 100.

 

i have

 

$100 = ($rows['views'] > '100');

 

 

but that's wrong. any help please?

[beansandsausages]

if($rows['views'] > 100 ) { echo " Do some thing "; } else { echo " do some thng else "; }

 

like that?

[KevinM1]

Remember - quotes denote strings (text).  To use numbers, simply write them without quotes.

[dachshund]

i don't want it to be an if statement. just $100 =

 

i tried without quotes but it still doesnt work.

[Zane]

variables can't begin with a number for one.

 

and secondly...  try this

 

$if100 = ($rows['views'] > 100) ? "Greater than 100" : "Not greater than 100";

[taquitosensei]

what's with the $if and $100    you can't begin a variable with a number. 

I also doubt you want a variable $if100.

 

why don't you tell us what you're actually trying to accomplish. That would help.

[Jezza]

$var = ($rows['views'] > 100)?true:false;

BAM hehe.

If the statement in the brackets is true return true, otherwise false.

Avoid using numbers at the start of variables and you're fine. Hope it helps.

this might help to understand this syntax.

Also when saying (greater than '100') don't use the quotes, treat it as a number.

echo "Hey, ".(($rows['views']>100)?"It's greater":"It's not greater")." and bye.";