Result depending on the incomming value of array

[gladz0r]

I've got the following script online: http://sbshasselt.be/ictco/maarten/icttips/index.php

It's in dutch but I'll explain the system, depending on the choice you make you'll get an result:

1. Show everything

2. Choose "Vak" - klas and eindterm stays <-- .. -->

..

 

This is the code u used (2. Choose "Vak" - klas and eindterm stays <-- .. -->):

if($leerjaar == '<-- Kies klas -->' && $eindterm == '<-- Kies eindterm -->' && $vak != '<-- Kies vak -->') 
{
?>

	<div align="center" class="style1"><b>Activiteiten voor <? echo $vak ?></b></div>
	<table width="100%" border="1">
		<tr>
   		     	<td width="50px" class="style7"><b><p class="style3">Oefening</p></b></td>
              	<td width="50px" class="style7"><b><p class="style3">Leerjaar</p></b></td>
			<td width="50px" class="style7"><b><p class="style3">Vak</p></b></td>
			<td width="50px" class="style7"><b><p class="style3">Lesonderwerp</p></b></td>
			<td width="50px" class="style7"><b><p class="style3">Doelstelling</p></b></td>
			<td width="20px" class="style7"><b><p class="style3">Media</p></b></td>
			<td width="50px" class="style7"><b><p class="style3">Eindterm</p></b></td>
		</tr>
<?php
		$sql = "SELECT * FROM `formulier` WHERE (`vak` = '$vak') ORDER BY leerjaar ASC";
		$qSelect_berichten  = $db->simpleQuery($sql) or die (mysql_error());
		while($db->fetchInto($qSelect_berichten, $aBerichten, DB_FETCHMODE_ASSOC))
		{
			echo '<tr>
			        <td width="50"><p class="style4">'.$aBerichten['id'].'</p></td>
           		    <td width="50"><p class="style4">'.$aBerichten['leerjaar'].'</p></td>
				<td width="50px"><p class="style4"><img src="vakken/'.$aBerichten['vak'].'.jpg" width="60" height="60" /></p></td>
				<td width="50px"><p class="style4">'.$aBerichten['lesonderwerp'].'</p></td>
				<td width="50px"><p class="style4">'.$aBerichten['doelstelling'].'</p></td>
				<td width="20px"><p class="style4"><a href="'.$aBerichten['ict2'].'" target="_blank"><img src="url.png" width="48" height="48" /></a></p></td>
				<td width="30%"><p class="style4">'.$aBerichten['eindterm'].'</p></td>
			</tr>';
	}
	echo '</table>';
}

 

Now I want to add the following code to my script, WHEN $aBerichten['ict2'] equals "http://"

<td width="20px"><p class="style4"><a href="'.$aBerichten['ict2'].'" target="_blank"><img src="url.png" width="48" height="48" /></a></p></td>

the site shoulld give no image in the column "MEDIA". http://sbshasselt.be/ictco/maarten/icttips/index.php .

Where and How shoulld i adjust this?

[andrewgauger]

I was in the process of modifying your code, but I think you made a mistake with your post because the conditional you requested would evaluate and then display the same for either case.  Your code provided is identical to the code in the sample.  Also--I visited your site and noticed the behavior you were requesting.  There were some media options that had no images.  Has this been resolved?