Trouble passing html form selection to php array on second page

[snailguy]

I have a working php page with an hmtl form where five names can be entered into five different text boxes.  Like so:

 

echo "<form name=\"formname\" action=\"form_review.php\" method=\"post\" enctype=\"multipart/form-data\">
<p>";
for ($i=0;$i<=4;$i++) {
  echo "First Name<input type=\"text\" name=\"firstnameT[".$i."]\" value=\"".($firstnameT[$i])."\" maxlength=\"15\">  ";
  echo "Last Name<input type=\"text\" name=\"lastnameT[".$i."]\" value=\"".($lastnameT[$i])."\" maxlength=\"15\"><br>";
}

 

On the page form_review.php:

 

//Convert POST variables to PHP
if (isset($_POST['firstnameT[]'])) {$firstnameT[]=$_POST['firstnameT[]'];}
else { $firstnameT[] = '';}
if (isset($_POST['lastnameT[]'])) {$lastnameT[]=$_POST['lastnameT[]'];}
else { $lastnameT[] = '';}

//Display the submitted data

for ($i=0;$i<=4;$i++) {
  echo "<p> $firstnameT[$i]." ".$lastnameT[$i]."<br>";
}
echo "</p>";	

 

 

So the problem I'm having is that I want to use <select><option> instead of <input type="text"> so users can select five names from five separate pull-down selectors, and display the selections on the next page, like so:

 

$query = "SELECT users.user_id, users.first_name, users.last_name, users.city
  FROM users";
$result = mysql_query($query) OR DIE("Your query failed: " .mysql_errno() . "    "  . mysql_error());
echo "<form name=\"formname\" action=\"form_review.php\" method=\"post\" enctype=\"multipart/form-data\">
for ($i=0;$i<=4;$i++) {
echo "<p><select name=\"volunteer[".$i."]\">";
echo "<option value=\"\">Choose a Volunteer</option>";
while($row = mysql_fetch_array($result)) {
	$vol_id = $row['user_id'];
	$first_name = $row['first_name'];
	$last_name = $row['last_name'];
	$city = $row['city'];
echo "<option value=\"".$vol_id."\">".$last_name.", ".$first_name." (".$city.")</option>";
} //close WHILE
echo "</select></p>";
mysql_data_seek($result,0); //reset the pointer in the result array for each FOR loop
} //close FOR

 

The above section of code works fine = the form displays properly, each pulldown has the full list of users, etc.  I have even confirmed that the underlying html has unique values for each pulldown choice, and that each pulldown choice has a unique name like:

 

<select name=volunteer[0]><option value="1">Last, First (city)</option><option value='2'>Last2, First2 (City2)</option></select>
<select name=volunteer[1]><option value="1">Last, First (city)</option><option value='2'>Last2, First2 (City2)</option></select>

 

But when I submit to review page, I can't get the selected names to display.  Here's the pertinent code from "form_review.php":

 

if (isset($_POST['volunteer[]'])) {$volunteer[]=$_POST['volunteer[]'];}
else { $volunteer[] = '';}
for ($i=0;$i<=4;$i++) {
  echo "Volunteer #".$i.":  ".$volunteer[$i]."<br>";
}
echo "</p>";

 

Unfortunately, nothing appears.  I'm expecting to get the selected option value following "Volunteer #:", but I'm not.  I've counted rows in the array passed to the second page and I consistently get numrows=1, and the value in that resulting array is obviously "". 

 

After five hours of trying a mind-numbing number of variations, I can't wrap my head around the solution.  Is there something special/different about passing arrays generated from <select><option> versus arrays generated from <input type=text>???

 

TIA!

 

snailguy

[Pikachu2000]

What does print_r($_POST) show you?

[snailguy]

[volunteer] => Array ( [0] => 1 [1] => 12 [2] => 2 [3] => 11 [4] => 3

 

That's good news.  The data is arriving at the second page intact.  Perhaps a problem with the POST to PHP variable conversion?

 

 

[snailguy]

This code:

 

echo "<p>ID's of trained volunteers:</p>
  <p>";
echo "volunteer array: ";
print_r($_POST[volunteer]);
echo "<br>trained = ".$trained."<br>";
$j = $trained-1;
for ($i=0;$i<=$j;$i++) {
echo "Volunteer #".$i.":  ".$volunteer[$i]."<br>";
}
echo "</p>";

 

Results in the following display:

 

ID's of trained volunteers:

volunteer array: Array ( [0] => 1 [1] => 12 [2] => 2 [3] => 11 [4] => 3 )
trained = 5
Volunteer #0:
Volunteer #1:
Volunteer #2:
Volunteer #3:
Volunteer #4: 

 

 

 

[greatstar00]

$volunteer[]=$_POST['volunteer[]'];

should be

$volunteer=&$_POST['volunteer[]'];

[kenrbnsn]

These two lines are wrong:

<?php
if (isset($_POST['volunteer[]'])) {$volunteer[]=$_POST['volunteer[]'];}
else { $volunteer[] = '';}
?>

Change them to

<?php
$volunteer = (isset($_POST['volunteer']))?$_POST['volunteer']:array();
?>

 

Ken

[snailguy]

Thanks!  After a nights sleep and a consult with a friend, I figured it out over breakfast.  Here is my solution:

 

if (isset($_POST['volunteer'])) {$volunteer = $_POST['volunteer'];}
else {$volunteer = '';} 

 

Jeff