PHP output Html Mess up

[Danny620]

<?php

    require('mysqli_connect.php');

 

// Query the database:

$q = "SELECT * FROM album";

$r = mysqli_query ($dbc, $q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc));

 

if (@mysqli_num_rows($r) == 1) { // A match was made.

 

echo '<select name="albumid" id="albumid">';

echo '<option value="1" selected="selected">Tribal</option>';

 

while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {

echo "<br /><option value="$row['albumid']">$row['name']</option>";

}

 

    '</select>';

 

}

?>

 

Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';' in C:\xampp\htdocs\upload\upload_image.php on line 147

[kenrbnsn]

Which line is 147?

 

Looking at you code, it's probably

<?php
echo "<br /><option value="$row['albumid']">$row['name']</option>";
?>

where you're missing some concatenation operators:

<?php
echo "<br /><option value=" . $row['albumid'] . ">$row['name']</option>";
?>

 

In the future, when you post code to this forum, please put your code between

tags.

 

Ken

[Danny620]

yes thats the line but i tryed replacing it with yours and all i got was

 

Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\xampp\htdocs\upload\upload_image.php  on line 147

[kenrbnsn]

Sorry, I didn't fix the other problem, try:

<?php
echo "<br /><option value=" . $row['albumid'] . ">" . $row['name'] . "</option>";
?>

or

<?php
echo "<br /><option value=" . $row['albumid'] . ">{$row['name']}</option>";
?>

 

Ken