If OR

[mcfmullen]

<?php 
if (trim($table) == 'pigs' || 'sheep' || 'goats' || 'cows' || 'flamingoes'){
echo "blah blah blah";
} else {
echo "bleep bleep bleep";
?>

 

The code above doesn't work. It echoes blah blah blah no matter what $table is set to. How am I supposed to use OR during an If statement?

[PFMaBiSmAd]

That's because trim($table) == 'pigs' is evaluated first, then the result of that is OR'd with 'sheep' and the result of that is OR'd with 'goats' ... The result of which is always TRUE.

 

You would need to write out each comparison or since you are comparing one variable with a list of values, use the in_array function.

[AbraCadaver]

$table = trim($table);
if ($table == 'pigs' || $table == 'sheep' || $table == 'goats' || $table == 'cows' || $table == 'flamingoes') {
   echo "blah blah blah";
} else {
   echo "bleep bleep bleep";
}

 

Or you can do something like:

$animals = array('pigs', 'sheep', 'goats', 'cows', 'flamingoes');

if(in_array(trim($table), $animals)) {
   echo "blah blah blah";
} else {
   echo "bleep bleep bleep";
}

[kenrbnsn]

That's not how you write the condition, use

<?php
if (trim($table) == 'pigs' || trim($table) == 'sheep' || trim($table) == 'goats' || trim($table) == 'cows' || trim($table) == 'flamingoes'){
?>

or you can use a switch statement:

<?php
switch (trim($table)) {
    case 'pigs':
    case 'sheep':
    case 'goats':
    case 'cows':
    case 'flamingoes':
        echo 'blah blah blah blah';
        break;
   default:
        echo 'bleep bleep bleep';
}
?>

 

Ken

[mcfmullen]

Thank you very much everyone!