Counting Number of Day's until a specific date

[leachus2002]

Hi All,

 

I was wondering if PHP is able to display the number of days until a specific date? For example - 10 days until July 16th?

 

Thanks

Matt

[bh]

Hi,

 

Your friend will be the time() function and strtotime().

 

Example:

 

$seconds = time() - strtotime(str_datatime_format);

[leachus2002]

Thanks for the prompt reply! But how to I specify the date in there?

[ChemicalBliss]

Easy, you can even do seconds, in fact its easier to do seconds with timestamps:

<?php

// The time your going to check against
$date1 = "25/12/2010"; // Christmas!

// Current timestamp (Current Date/Time)
$current = time();

// Convert that date string above into a timestamp as well.
$until = strtotime($date1);

// Get the difference in seconds between two dates. (Very simple math)
$difference = $until - $current;

// Get number of days (Also very simple math)
$days = (($difference / 60) / 60) / 24; // Seconds / minutes / hours / days

// Results
echo("Number of days until christmas: ".$days." - Number of Seconds: ".$difference."<br />");

?>

 

Hope this helps,

-cb-

 

[leachus2002]

Hey CB,

 

Nice coding, thanks for sending that over! I have tried it, but unfortunately I am getting a long decimal number - for example if I set the date as christmas - I get 14796.6248598

 

Any Ideas?

 

Cheers

Matt

[Pikachu2000]

Look at the date_diff() function. (link) It might work better for this application.

[ChemicalBliss]

Oops, strtotime doesnt understand " / ", change the " / " in the date to " - ", eg: 25-12-2010

 

Also you can use round() to get a less specific long number. or floor() to remove the decimal entirely.

 

-cb-

 

NOTE: As pikachu said you could use the DateTime Object (if you have PHP 5.3 or greater). - To get your version use phpinfo();

[AbraCadaver]

Oops, strtotime doesnt understand " / ", change the " / " in the date to " - ", eg: 25-12-2010

 

Also you can use round() to get a less specific long number. or floor() to remove the decimal entirely.

 

-cb-

 

NOTE: As pikachu said you could use the DateTime Object (if you have PHP 5.3 or greater). - To get your version use phpinfo();

 

strtotime() treats dates with / as mm/dd/yyyy and dates with - as dd-mm-yyyy or yyyy-mm-dd.

[leachus2002]

Hey Everyone,

 

I have tried incorporating round() and datediff() into this, but I am struggling to get my head around it, can someone point me in the right direction please?

 

Cheers

Matt

[myrddinwylt]

Hello,

 

Here is a very simple way to get this done

 

// Define final day -- if this is less than the $startdate, then I am not sure what will happen  ^.^
$enddate = "2010-12-25";

// Calculation of difference between now, and the end date
$startdate = time();
$enddate = strtotime($enddate);
$diff = $enddate - $startdate;
$days = ceil($diff / 86400);

// Output total
echo $days;