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Error when extracting data from MySQL .. ?


dominod

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Hi

 

I am having troubles extracting data from my MySQL database.. The strange thing is that this code has worked before.. I just copied and pasted (changing the nessessary names of cource).

 

<?php
ini_set("display_errors", true);
error_reporting(-1);

include("connect.php");

$extract = mysql_query("SELECT * FROM suggest");
$numrows = mysql_num_rows($extract);

while ($row = mysql_fetch_array($extract))
{
$url[$i]=$row['url'];
$i++;
}

$id=1;
while($id < count($name))
  {
  echo "The URL is " . $url[$id] . "<br />";
  $id++;
  }



?>

 

And the error msg I get is:

 

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/haukaas/public_html/new/suggest-search-engine/admin/index.php on line 8

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/haukaas/public_html/new/suggest-search-engine/admin/index.php on line 10

Notice: Undefined variable: name in /home/haukaas/public_html/new/suggest-search-engine/admin/index.php on line 17

 

Can anyone help me?  :(

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https://forums.phpfreaks.com/topic/207838-error-when-extracting-data-from-mysql/
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Ok now it works ... I was trying to connect to the wrong database (Stupid me! Yes I know!)

 

I also made some changes to the code and now all the error msg is gone and it is diplaying the last entry in the mysql db.

 

How can I make it display all entries?

 

Here is the code:

<?php
ini_set("display_errors", true);
error_reporting(-1);

include("connect.php");

$extract = mysql_query("SELECT * FROM suggest");
$numrows = mysql_num_rows($extract);

while ($row = mysql_fetch_array($extract))
{
$url=$row['url'];
}


  echo "The URL is " . $url . "<br />";

?>

 

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