next page's link on return of query ?

nbbcj · August 22, 2010

hi there alll newbie here lol

just needed help with the code for the next page of results ?

IE i have say 30 results returned from a sql query but only want to show ten at a time i no how to limit the result with the LIMIT 10 but how do i get it to put link show the other ten and so on.

the code i have is here at the bottom of page http://www.phpfreaks.com/forums/index.php/topic,307971.0.html

thanks in advance for any help

kaine

premiso · August 22, 2010

You want pagination. A tutorial can be found on this site called Basic Pagination. I would suggest reading up on it. If you have issues, post your questions here with code so we can further help you.

nbbcj · August 22, 2010

Thanks premiso that link was just what im looking for the only prob i have now is putting it with my code

im getting this error Fatal error: SQL in /customers/nbbcj.co.uk/nbbcj.co.uk/httpd.www/testd/test.php on line 10

with this code ###### i wanted to leave the $cat bit in so i can use the dropdown menu i have alredy on page

<?php error_reporting(E_ALL) ; ini_set('display_errors','1'); ?>
<html>

<head>
<meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
<title>test page one</title>
</head>

<body>
Welcome to the test page #
<form method="POST" action="test.php">
<select size="1" name="D1">
<option value="audio">audio</option>
<option selected value="internet">internet</option>
<option value="file man">file man</option>
<option value="games">games</option>
</select><input type="submit" value="Go Get It"></p>
</form>
Ues the drop down box to select the cat you want 
<?php
//thanks to Crayon Violent for the pagination code 
// database connection info
$conn = mysql_connect('conn','user','pass') or trigger_error("SQL", E_USER_ERROR);
$db = mysql_select_db('db name',$conn) or trigger_error("SQL", E_USER_ERROR);

// find out how many rows are in the table 
$cat = mysql_real_escape_string($_POST['D1']); 
$sql = "SELECT COUNT(*) FROM penapps WHERE `cat` = '$cat' LIMIT 10";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);
$r = mysql_fetch_row($result);
$numrows = $r[0];

// number of rows to show per page
$rowsperpage = 10;
// find out total pages
$totalpages = ceil($numrows / $rowsperpage);

// get the current page or set a default
if (isset($_GET['currentpage']) && is_numeric($_GET['currentpage'])) {
   // cast var as int
   $currentpage = (int) $_GET['currentpage'];
} else {
   // default page num
   $currentpage = 1;
} // end if

// if current page is greater than total pages...
if ($currentpage > $totalpages) {
   // set current page to last page
   $currentpage = $totalpages;
} // end if
// if current page is less than first page...
if ($currentpage < 1) {
   // set current page to first page
   $currentpage = 1;
} // end if

// the offset of the list, based on current page 
$offset = ($currentpage - 1) * $rowsperpage;

// get the info from the db 
$sql = "SELECT id, number FROM numbers LIMIT $offset, $rowsperpage";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);

// while there are rows to be fetched...
while ($list = mysql_fetch_assoc($result)) {
   // echo data
   echo $list['id'] . " : " . $list['number'] . "<br />";
} // end while

/******  build the pagination links ******/
// range of num links to show
$range = 3;

// if not on page 1, don't show back links
if ($currentpage > 1) {
   // show << link to go back to page 1
   echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=1'><<</a> ";
   // get previous page num
   $prevpage = $currentpage - 1;
   // show < link to go back to 1 page
   echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$prevpage'><</a> ";
} // end if 

// loop to show links to range of pages around current page
for ($x = ($currentpage - $range); $x < (($currentpage + $range) + 1); $x++) {
   // if it's a valid page number...
   if (($x > 0) && ($x <= $totalpages)) {
      // if we're on current page...
      if ($x == $currentpage) {
         // 'highlight' it but don't make a link
         echo " [<b>$x</b>] ";
      // if not current page...
      } else {
         // make it a link
         echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$x'>$x</a> ";
      } // end else
   } // end if 
} // end for
                 
// if not on last page, show forward and last page links        
if ($currentpage != $totalpages) {
   // get next page
   $nextpage = $currentpage + 1;
    // echo forward link for next page 
   echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$nextpage'>></a> ";
   // echo forward link for lastpage
   echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$totalpages'>>></a> ";
} // end if
/****** end build pagination links ******/
?>
########################################
i also tryed it like this 

// find out how many rows are in the table 
// $cat = mysql_real_escape_string($_POST['D1']); 
$sql = "SELECT COUNT(*) FROM penapps ";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);
$r = mysql_fetch_row($result);
$numrows = $r[0];

but just get blank page

please help its driving me mad lol

thanks in advance

kaine

nbbcj · August 22, 2010

just a side note does my db need to have index defined ????

.josh · August 22, 2010

dumb question, but did you change the info you need to supply in

$conn = mysql_connect('conn','user','pass') or trigger_error("SQL", E_USER_ERROR);
$db = mysql_select_db('db name',$conn) or trigger_error("SQL", E_USER_ERROR);

jcbones · August 22, 2010

Your two sql query's don't match, the count is coming from penapps, and your data is coming from numbers.

nbbcj · August 22, 2010

dumb question, but did you change the info you need to supply in

$conn = mysql_connect('conn','user','pass') or trigger_error("SQL", E_USER_ERROR);
$db = mysql_select_db('db name',$conn) or trigger_error("SQL", E_USER_ERROR);

yer changed the conn,user,and pass and db name t there proper ones

nbbcj · August 23, 2010

Alll Sorted now thank u every one did a bit of fiddling and it works now part form one thing

If you could help again please

i can get the dropdown box working but not when i change page it drops the cat selection and no results.

I got the ddb to work by changing.....

// get the info from the db

$sql = "SELECT * FROM penapps LIMIT $offset, $rowsperpage";

$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);

to

// get the info from the db

$cat = mysql_real_escape_string($_POST['D1']);

$sql = "SELECT * FROM penapps WHERE `category` = '$cat' LIMIT $offset, $rowsperpage";

$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);

Witch make this work

<option selected value="audio">audio</option>

<option value="internet">internet</option>

<option value="games">games</option>

</select><input type="submit" value="Go Get It"></p>

</form>

But any help on getting the ddm selection to stay after page change may be by adding $cat to this

echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=1'><<</a> ";

// get previous page num

$prevpage = $currentpage - 1;

// show < link to go back to 1 page

echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$prevpage'><</a> ";

thanks in advance

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