Phpfr3ak Posted October 19, 2010 Share Posted October 19, 2010 Hi for some reason i get parse error: syntax error, unexpected T_EXIT in C:\Program Files\EasyPHP-5.3.3\www\htdocs\attack_code.php on line 44, im unsure as to why as the code below looks good to me? If its wrong could someone correct em and explain as to why Thanks if($playerID == $defender) { echo "<div>You can't attack yourself.</div>"; include("exit.php"); exit; }else{ if($timesince < 10800){ echo "You can only attack the same player once every 3 hours."; include("exit.php") exit; }else{ if($hits < 1){ echo "You have no available hits. New hit allowances are granted every ten minutes on the :05's"; include("exit.php") exit; }else{ the part below the last }else{ is irrelevant and works so Ive not included Link to comment https://forums.phpfreaks.com/topic/216210-unexpected-t_exit/ Share on other sites More sharing options...
hitman6003 Posted October 19, 2010 Share Posted October 19, 2010 Which line is 44? Link to comment https://forums.phpfreaks.com/topic/216210-unexpected-t_exit/#findComment-1123662 Share on other sites More sharing options...
kenrbnsn Posted October 19, 2010 Share Posted October 19, 2010 You forgot the terminating semi-colon on two of these lines: <?php include("exit.php") ?> Ken Link to comment https://forums.phpfreaks.com/topic/216210-unexpected-t_exit/#findComment-1123663 Share on other sites More sharing options...
Phpfr3ak Posted October 19, 2010 Author Share Posted October 19, 2010 Doohh can't believe i missed that, Thank you very much. Link to comment https://forums.phpfreaks.com/topic/216210-unexpected-t_exit/#findComment-1123664 Share on other sites More sharing options...
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