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Hi Guys,
I'm having some problems with the code below. Could someone take a look and point me in the right direction.

Basically I have a list of news articles and I want to display the top three by date in descending date order. The code below works fine untill I include the "TOP 3" part of the SQL query at which point I get the following error message:

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\Intranet v3\TEST\News\Top_3_Articles.php on line 25

$result = mysql_query("SELECT TOP 3 * FROM tbl_news ORDER by Date DESC",$db);

echo "<p class='Body2'>Select news article to display...</p>";
echo "<table width=80% border=1>\n";
echo "<tr class='Body2' bgcolor=#CCCCCC><th>Date</th><th>Heading</th></tr>\n";
//colum names

while ($myrow = mysql_fetch_array($result)) {

printf("<tr><td>%s</td><td><a href=\"%s?id=%s\" class='Body2'>%s</a></td></tr>\n",
//lay out results 2 in the first column and 1 in the second
$myrow["Date"], "Result_ByArticle.php", $myrow["ID"], $myrow["Title"]);

echo "</table>\n";

Any help would be appreciated as I just can't see where this is going wrong!

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Use this instead.
$query="SELECT * FROM tbl_news ORDER by Date DESC LIMIT 0,3"
$result = mysql_query($query) or die(mysql_error());

This should bring the query out ok. I haven't looked at the rest of the code to see if that will work.

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TOP was an mssql 2005 syntax. So it wont work on mysql.

Even if there is a sql standart, most of the companies add their own features on them to be selected more. But above some expections like this, the sql syntax is the same.

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