Help with Ajax and PHP search autofill

Lostnode · October 27, 2010

Ok, this is stumping my mind. I have a PHP/AJAX script which works almost perfectly. But its lacking one detail I absolutely need. Every AJAX demo I have seen is missing it or doesn't work right.

Here is where the problem is.

I have a list of countries, I want the user to spell it right when using my search, so you put in say "Virgin Islands"

It should pull up the following in the list:

Virgin Islands (British)

St. Thomas (U.S. Virgin Islands)

However all I get is:

Virgin Islands (British)

It has to do with the MySQL Query...

Here is what came with the demo:

$query = sprintf("SELECT ctry_name  
FROM international 
WHERE ctry_name '%s%%'  
GROUP BY ctry_name",
$ctry_name);

That's what pulls up only Virgin Islands

I tried to mod the query to be

"SELECT ctry_name FROM interntaional WHERE ctry_name LIKE '%" . $ctry_name . "%'"

But it breaks the script, in other AJAX Examples, it doesn't even look it up and returns all entries in the database.

Like I said the above example works fine, it just returns just the one value, I want ti to return all variables.

darkfreaks · October 27, 2010

why does it need to be changed first off and second post the full script and more detail. :confused:

darkfreaks · October 27, 2010

what about the following script?

http://www.devbridge.com/projects/autocomplete/jquery/

seems to work and its fully uses Jquery and Ajax.

Lostnode · October 27, 2010

why does it need to be changed first off and second post the full script and more detail.

It needs to change so that when a User Types Virgin Islands, It comes up with both:

Virgin Islands (British)

St. Thomas (U.S. Virgin Islands)

Not just Virgin Islands (as stated above in my original post.)

The link you gave does the same thing, its almost what I want, just it takes the first part of what you typed in, I.E. When I type the letter V I get only what starts with V, not what contains a V.

If I type V I should get everything that starts with a V, ends with a V and contains a V somewhere within.

% $variable % is supposed to work according to a whole lot of forums out there, however it doesn't seem to work with Ajax.

Here are the 4 original files (unedited) that I picked up.

ajax-test.php

<html>
<head>
<title>AJAX testing</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<script language="JavaScript" type="text/javascript" 
	src="JsonRequest.js"></script>
<script>

//slow down the event handler...
var searching;
function doRequestTimeout(dat){
	clearTimeout(searching);
	searching = setTimeout('doRequest("'+dat+'")', 300);
}

//display data returned by ajax...
function display(data){
	var displayDiv;
	displayDiv = document.getElementById("cityList");

	//set to visible if not already
	displayDiv.style.display = 'block';
	displayDiv.innerHTML = '';

	//start the unordered list
	displayDiv.innerHTML = '<ul class="cities">';

	//populate the list
	for(i in data){
		displayDiv.innerHTML += '<li><a href="#" onClick="populateTextField(\''+data[i]+'\');">'+data[i]+'</a></li>';
	}

	//end the unordered list
	displayDiv.innerHTML += '</ul>';
}

//declare url for json requests...
var url = 'ajax-query.php'

//create json request object
//arguments own name, callback function to process data once request has been made
var json = new JsonRequest('json', new Function('data', 'display(data)'));

//function to be called to get the results from the server
function doRequest(text){
	json.makeRequest(url+"?city="+text);
}

//populate the text field with the result that was clicked on
function populateTextField(datum){
	document.getElementById("cityField").value = datum;
	document.getElementById("cityList").style.display = 'none';
}

</script>
<style>


#cityList ul{
	margin: 0px;
	padding: 0px;
}

#cityList li{
	display:block;
}

#cityList li a {
	border-bottom: 1px solid #fff;
	display: block;
	padding-left: 10px;
	font-family: arial;
	font-weight: bold;
	font-size: 11px;
	text-decoration: none;
	background: #B3B3B5;
	color: #fff;
}

#cityList li a:hover {
	background: #37445E;
}
</style>
</head>

<body>

<input type="text" name="city" id="cityField" onKeyUp="doRequestTimeout(document.getElementById('cityField').value);">

<div id="cityList" style="width:360px;"></div>

</body>
</html>

ajax-query.php

<?
//######################################################################
//connect to the database etc.

## Database Connection
define(DB_HOST, "localhost"); 
 # DB Username
define(DB_USER, "");
 # DB password
define(DB_PASS, "");
 # DB to select - Database Name
define(DB_NAME, "dbname");

//mysql_connect(DB_HOST, DB_USER, DB_PASS) or die(mysql_error());

//mysql_select_db(DB_NAME);

//returns array of database result
function db_num_ajax($sql){

	$q = mysql_query($sql) or die(mysql_error());
	$result = array();

	while($row = mysql_fetch_array($q, MYSQL_NUM)){
		array_push($result, $row);
	}

mysql_free_result($q);
return $result;
}
//######################################################################

include_once('Services_JSON.php');

//make json object...
$json = new Services_JSON();

//get array of data
//$data = getData($_GET);
$data = getData($_GET[city]);

//send no-cache header (otherwise IE caches ajax requests)...
header("Cache-Control: no-cache");

//encode and return json data...
echo $json->encode($data);

function getData($city){
	$query = sprintf("SELECT debtors_city  
						FROM debtors 
						WHERE debtors_city LIKE '%s%%'  
						GROUP BY debtors_city",
						$city);
	$result = db_num_ajax($query);
	return $result;

}


?>

JsonRequest.js

function JsonRequest(mn,callback){
this.mn = mn;
this.cb = callback;
this.rObj = this.makeObj();
};

JsonRequest.prototype.makeRequest = function(url,p){
// return false if no XHR object, so that form/link whatever will know to submit manually
if (!this.rObj) return false;
if (!p) p = false;

// set up the request
if (p){
	this.rObj.open('POST', url, true);
	this.rObj.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
	this.rObj.setRequestHeader("Content-length", p.length);
	this.rObj.setRequestHeader("Connection", "close");
}
else this.rObj.open('GET', url, true);

// set the callback function
if (this.cb) this.rObj.onreadystatechange = new Function('if ('+this.mn+'.rObj.readyState == 4) '+this.mn+'.cb(eval("("+'+this.mn+'.rObj.responseText+")"));');
else this.rObj.onreadystatechange = function(){return};

// send the request
this.rObj.send(p ? p : null);

// return true- TODO: return false if request somehow fails...
return true;
};

JsonRequest.prototype.makeObj = function(){
if (window.XMLHttpRequest) // Mozilla, Safari,...
	r = new XMLHttpRequest();
  else if (window.ActiveXObject) { // IE
    try {
        r = new ActiveXObject("Msxml2.XMLHTTP");
    } catch (e) {
      try {
          r = new ActiveXObject("Microsoft.XMLHTTP");
      } catch (e) {}
  }}
return r ? r : false;
};

Lostnode · October 27, 2010

The 4th is attached, too big to type out, and as I can tell has no bearing on the output other than mine tweaking.

Again, I need it to pull entries that CONTAIN the search parameter and not START WITH the search parameter... THis is why it needs to be changed.

[attachment deleted by admin]

BlueSkyIS · October 27, 2010

one option: change the query to this:

$city = mysql_real_escape_string($city);

$query = "SELECT debtors_city  
						FROM debtors 
						WHERE debtors_city LIKE '%$city%'  
						GROUP BY debtors_city";

Lostnode · October 27, 2010

one option: change the query to this:

$city = mysql_real_escape_string($city);

$query = "SELECT debtors_city  
						FROM debtors 
						WHERE debtors_city LIKE '%$city%'  
						GROUP BY debtors_city";

DING DING DING, WE HAVE A WINNER - Thank you very very much, this works like a charm.

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