Simple date calc

[johnsmith153]

I need to work out the months remaining of someone's membership when the date provied is in the format dd/mm/YYYY - rounded down to one month.

 

So, today being Nov 6th if the membership expired on 10th Feb then this would return 3.

 

1st Feb would be 2 etc..

[mike12255]

Do you have the date entered into a database?

[litebearer]

Perhaps...

 

<?PHP
function MonthDiff($start_date, $end_date) {
$array01 = explode("/", $start_date);
$array02 = explode("/", $end_date);
$start_date2 = $array01[1] . "/" . $array01[0] . "/" . $array01[2]; 
$end_date2 = $array02[1] . "/" . $array02[0] . "/" . $array02[2]; 
$ts1=strtotime($start_date2);
$ts2=strtotime($end_date2);
$m_diff = floor(($ts2-$ts1)/2628000);
return $m_diff;
}
$start_date = "06/11/2010";
$end_date = "10/02/2011";
echo MonthDiff($start_date, $end_date);
$end_date = "01/02/2011";
echo "<br>";
echo MonthDiff($start_date, $end_date);
?>