Getting variable from current URL

[OhTheNoes]

Hello! Once again, I find myself in the need of help regarding PHP.

 

What I have is a URL that looks like this:

http://domain.com/gallery/?album=3&gallery=65

 

What I need is to extract the number that comes after "album=". In this case, it would be the number 3.

 

I currently have this:

<?php $url=getPageURL(); $var=explode('album=',$url); $var=explode('?',$var[1]); ?>

 

My problem is that it doesn't result in anything.

 

Can anyone lend a hand? It would be much appreciated.

[Adam]

If this is something you'll be using several times, you may want to consider creating a function in combination with parse_url to return parameters in the query string. There's an example in a comment on the PHP manual.. Or if this is just a one-off case you could use preg_match:

 

$url = 'http://domain.com/gallery/?album=3&gallery=65';

if (preg_match('/album\=([^&$]+)/', $url, $matches))
{
    echo $matches[1];
}

[OhTheNoes]

Hello! Thank you for taking the time to help me out.

 

The code will be placed in a template file which will be called(?) each time someone opens a gallery page.

 

To give a wider view, I'm trying to insert a "back to album" link in each gallery page.

 

My original, incorrect code:

<?php $url=getPageURL(); $var=explode('album=',$url); $var=explode('?',$var[1]); ?>
<?php $albumVar=$var[1] ?>
Back to <a href="http://domain.com/gallery/?album=<?php echo $albumVar ?>">gallery</a>

 

Do you suggest I go with the function you mentioned or would the code you supplied be alright for this purpose?

[salathe]

You could also use parse_str to make sense of the query string.

 

$url = 'http://domain.com/gallery/?album=3&gallery=65';

// album=3&gallery=65
$query_str = parse_url($url, PHP_URL_QUERY);

// array('album' => '3', 'gallery' => '65');
parse_str($query_str, $query_arr);

// outputs: 3
echo $query_arr['album'];

 

That could be mushed on to one line, for you to echo as you want:

<?php parse_str(parse_url(getPageURL(), PHP_URL_QUERY), $query_arr); ?>
Back to <a href="http://domain.com/gallery/?album=<?php echo urlencode($query_arr['album']) ?>">gallery</a>

[OhTheNoes]

Fantastic. It works perfectly.

 

You guys are the absolute best. Thanks very much salathe, MrAdam!

[trq]

Whats wrong with $_GET['album'] ? Or have I missed something completely?

[Adam]

I thought that at first Thorpe, but based on his original question it looked like he was dealing with a string. After the comment about getting back to the parent album though I'm not sure..?

[trq]

The subjects says "Getting variable from current URL". Maybe the OP should clarify.

[Adam]

Aha oh yer 

[OhTheNoes]

The subjects says "Getting variable from current URL". Maybe the OP should clarify.

 

Sorry! I am not very familiar with PHP terminology so I may have misrepresented some things with my words of choice.

 

What can I do to help clarify the situation?

[Adam]

Are you wanting to return the "album" parameter from the URL the user is visiting, or from a URL contained within a variable?

[bob2006]

would it be easier to wirte the code like this

<?php
$album=$_GET['album'];
$gallery=$_GET['gallery'];
echo"$album<br>$gallery";

 

if it not please forgive me for opening my big mouth

[Adam]

would it be easier to wirte the code like this

<?php
$album=$_GET['album'];
$gallery=$_GET['gallery'];
echo"$album<br>$gallery";

 

if it not please forgive me for opening my big mouth

 

Think that was the point of Thorpe's post to be honest.

[plznty]

The subjects says "Getting variable from current URL". Maybe the OP should clarify.

I was thinking exactly the same. haha. Use $_GET.

[OhTheNoes]

Are you wanting to return the "album" parameter from the URL the user is visiting, or from a URL contained within a variable?

 

From the URL the user is visiting. I'm sorry if I made things look confusing

 

What I meant from my title was how to get the album number which varies depending on the URL of the user.

[bob2006]

that what i allways use works fine for me

[trq]

What I meant from my title was how to get the album number which varies depending on the URL of the user.

 

That would be as simple as.....

 

$album = $_GET['album'];

 

[OhTheNoes]

Oh I see!

 

Would that work with everything in the format of x=y and you want to get y?

[trq]

Yes.

[OhTheNoes]

Ah great. Fantastic. Thank you all for your help, not just with this problem, as I'm sure this will definitely help me a lot in the future. Thank you!