richarro1234 Posted November 20, 2010 Share Posted November 20, 2010 Hey all, im trying to make a script that will show the hours i have worked and how much i get for that day, then i need to add all the days up and output the total at the bottom of the page. So say i get £5 an hour and i do 4 hours one day 1 and 5 hours on day 2 So far the database outputs all the data like this: day1 - in 12:00, out 16:00 (hours) (£20) day2 - in 12:00 out 17:00 (5hours) (£25) now i need to add up the total for each day and output the grand total (so 20+25=£45) But i also need it to be able to add if i add a day aswell so day3 - in 12:00 out 17:00 (5hours) (£25) so now the total at the bottom of the page would be £70 Hope this makes sense to everyone, i have my code if anyone needs to see it. Thanks Rich Quote Link to comment https://forums.phpfreaks.com/topic/219266-need-help-please/ Share on other sites More sharing options...
trq Posted November 20, 2010 Share Posted November 20, 2010 i have my code if anyone needs to see it. Impossible to help you without it. Also, you haven't actually asked any question. Do you have one? Quote Link to comment https://forums.phpfreaks.com/topic/219266-need-help-please/#findComment-1137068 Share on other sites More sharing options...
richarro1234 Posted November 20, 2010 Author Share Posted November 20, 2010 <?php $mysql_hostname = "localhost"; $mysql_user = ""; $mysql_password = ""; $mysql_database = ""; $bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Could not connect database"); mysql_select_db($mysql_database, $bd) or die("Could not select database"); ?> <?php $results= mysql_query("SELECT * FROM hours WHERE year = '2010'"); echo mysql_error(); if (mysql_Numrows($results)>0) //if there are records in the fields { $numrows=mysql_NumRows($results); //count them $x=0; while ($x<$numrows){ //loop through the records $thetimein=mysql_result($results,$x,"timein"); $thetimeout=mysql_result($results,$x,"timeout"); $theday=mysql_result($results,$x,"daynumber"); $themonth=mysql_result($results,$x,"month"); $theyear=mysql_result($results,$x,"year"); $worked = $thetimeout-$thetimein; $totalpay = $worked*6.40; ?> <?php echo" $theday/$themonth/$theyear: $thetimein - $thetimeout ($worked) = (£$totalpay)"; ?><br> <?php $x++; } } ?> <BR> Total pay so far is: <?php echo"$totalpay"?> Thats the code i have so far The question is: How do i do it please. Rich Quote Link to comment https://forums.phpfreaks.com/topic/219266-need-help-please/#findComment-1137070 Share on other sites More sharing options...
DavidAM Posted November 20, 2010 Share Posted November 20, 2010 $x=0; $GrandTotal = 0; while ($x<$numrows){ //loop through the records // all your other code as is $totalpay = $worked*6.40; $GrandTotal += $totalpay; $x++; } } ?> <BR> Total pay so far is: <?php echo"$GrandTotal"?> Quote Link to comment https://forums.phpfreaks.com/topic/219266-need-help-please/#findComment-1137077 Share on other sites More sharing options...
richarro1234 Posted November 20, 2010 Author Share Posted November 20, 2010 Awesome, Thank you very much DavidAM works a charm... Thanks so much Rich Quote Link to comment https://forums.phpfreaks.com/topic/219266-need-help-please/#findComment-1137079 Share on other sites More sharing options...
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