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I am creating a site that has to display 36 images on the screen.  The image name is stored in the database.  My problem is if I have less than 36 images stored I need to display a default image.  here is my current query

 

$sql="SELECT col_image, col_url from tbl_images WHERE col_active='1' and col_bigimage='0' ORDER BY RAND() limit 36";

 

so If I only have 20 active images. I need to display 16 default images.  I hope this makes sense.

 

Bill

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