in_array not working?

[karimali831]

Hi folks!

 

I have two arrays:

 

1)

print_r($users1); 

Array ( [0] => 1 [1] => 2609 [2] => 2612 [3] => 2620 [4] => 2621 [5] => 2624 [6] => 2627 [7] => 2629 )

 

2)

print_r($users2); 

Array ( [0] => 1 [1] => 2609 [2] => 2610 [3] => 2611 [4] => 2612 [5] => 2617 [6] => 2618 [7] => 2619 [8] => 2620 [9] => 2621 [10] => 2624 [11] => 2625 [12] => 2626 [13] => 2627 [14] => 2628 [15] => 2629 )

 

now why does nothing return when I use in_array?

 

if(in_array($users1,$users2)) 
  return true;

 

all values in $users1 is in $users2...

 

Please help, need help fast!

 

Thank you

[kenrbnsn]

Because that's not what the function in_array does.

 

You can write a small function that does what you want:

<?php
function my_in_array($ary1,$ary2) {
  $ret = true;
  foreach($ary1 as $v) {
     if (!in_array($v,$ary2)) {
        return false;
     }
  }
  return $ret;
}

$users1 = array(1,2609,2612,2620,2621,2624,2627,2629);
$users2 = array_merge(array(1),range(2609,2629)); 
echo '<pre>' . print_r($users1,true) . '</pre>'; //debug
echo '<pre>' . print_r($users2,true) . '</pre>'; //debug
if (my_in_array($users1,$users2)) {
    echo "yes";
} else {
    echo "no";
}
?>

 

Ken

 

 

[BlueSkyIS]

or this might work

 

$u1_count = count($users1);
$diffs = array_diff($users1,$users2);
if (count($diffs) != $u1_count) {
     // There is at least one match...
} else {
     // There are no matches (all in $users1 are different from $users2)
}

[karimali831]

Thanks for your help, I will try this but before I do...

 

only this bit I am not sure what to do with:

 

$users1 = array(1,2609,2612,2620,2621,2624,2627,2629);
$users2 = array_merge(array(1),range(2609,2629)); 

 

I get my arrays from query:

 

    $qual = safe_query("SELECT * FROM ".PREFIX."cup_clans WHERE groupID='$ID' && $type='0' && qual='1' && pm='0'");
      while($iq = mysql_fetch_array($qual)) {
        $qualified_ID[]=$iq['clanID'];
    }
    
    $participants = safe_query("SELECT * FROM ".PREFIX."cup_clans WHERE groupID='$ID' && $type='0'");
      while($all = mysql_fetch_array($participants)) {
        $user[]=$all['clanID'];
    }

 

        if(my_in_array($user,$qualified_ID))

          return true;

 

does not return true however

or should it?

[kenrbnsn]

The $users1 & $users2 in my code was just a way of populating the arrays like you had them in your code.

 

Try reversing the order of the input parameters to my function. The first parameter is the array that contains the smaller number of elements.

 

What are you trying to accomplish. There may be an easier way to do it using one MySQL query.

 

Ken

 

[karimali831]

Yes I understand that but this..

 

$users2 = array_merge(array(1),range(2609,2629));

 

you are merging and using range? why I must do this?

I don't know what to put in range.

[kenrbnsn]

You don't have to use $user2, that was just there so I had two arrays that looked like yours. A print_r of $user2 would show:

Array
(
    [0] => 1
    [1] => 2609
    [2] => 2610
    [3] => 2611
    [4] => 2612
    [5] => 2613
    [6] => 2614
    [7] => 2615
    [8] => 2616
    [9] => 2617
    [10] => 2618
    [11] => 2619
    [12] => 2620
    [13] => 2621
    [14] => 2622
    [15] => 2623
    [16] => 2624
    [17] => 2625
    [18] => 2626
    [19] => 2627
    [20] => 2628
    [21] => 2629
)

 

Ken

[karimali831]

Ahh thanks very much, figured it with the code you mentioned

 

   foreach($qualified_ID as $v) {
      if (in_array($v,$user)) {
         sendmessage($v, $sm_elig_subject, $sm_qualified);
      }