If Elseif

[gunthertoody]

I am  a novice and had this code below working fine until I added the If / elseif to "plan_id".  Prior, the column would just list out the numbers from the database, but I want the numbers to echo out the text. Any help is appreciated.

 

while($row = mysql_fetch_array($result)){

 

  $bg = ($bg=='#ffffff' ? '#e7e8e8' : '#ffffff'); //For Alternate Row Colors

 

echo '<tr bgcolor="' . $bg . '"><td>' . $row['customers_firstname'] . " " . $row['customers_lastname'] . '</td><td>' . date("M. d, Y", strtotime($row['date'])) . '</td><td>' . if ($row['plan_id'] == 1) {

echo "1 DVD";

}

elseif ($row['plan_id'] == 2) {

echo "2 DVDs";

}

else {

echo "3 DVDs";

}

. '</td></tr>';}

echo '</table>';

echo '<br />';

[Skepsis]

what output are you getting? does it display 1,2 or 3 DVD's?

 

Anyhow, try this code:

 

$idx = 0;
while($row = mysql_fetch_array($result))
{
    $idx++;
    $bg = ($bg=='#ffffff' ? '#e7e8e8' : '#ffffff'); //For Alternate Row Colors
   
    echo '<tr bgcolor="' . $bg . '">
            <td>' . $row['customers_firstname'] . $row['customers_lastname'] . '</td><td>' . date("M. d, Y", strtotime($row['date'])) . '</td><td>';
            if ($idx == 1) 
            {
                echo $idx.' DVD';
            }
            else {
                echo $idx.' DVDs';
            }

    echo '</td></tr>';
}
echo '</table><br />';

 

$idx = 0; is what defines the variable

$idx++; increments the value by one each time the loop loops.

the if statement checks if there is one dvd and prints the non plural form of dvd, if it's not one it displays the plural form.

hope this helps.

[gunthertoody]

Thanks, but I'll clarify. The "plan_id" column currently holds either 1, 2 or 3 as values. I just want to change the value from a number to text.

 

Desired results:

when plan_id = 1    echo "1 DVD"

when plan_id = 2    echo "2 DVDs"

when plan_id = 3    echo "3 DVDs"

[Skepsis]

Alrighty then, go ahead and use this code

<?php
while($row = mysql_fetch_array($result))
{
    $bg = ($bg=='#ffffff' ? '#e7e8e8' : '#ffffff'); //For Alternate Row Colors
   
    echo '<tr bgcolor="' . $bg . '">
            <td>' . $row['customers_firstname'] echo '</td><td>';
    if ($row['plan_id'] == 1) 
    {
        echo '1 DVD';
    }
    elseif ($row['plan_id'] == 2) 
    {
        echo '2 DVDs';
    }
    else {
        echo '3 DVDs';
    }     
    echo '</td></tr>';
}
echo '</table><br />';
?>['php]

[gunthertoody]

Thanks but it's still not working :'(

 

Second looks appreciated.

 

The "plan_id" column currently holds either 1, 2 or 3 as values. I just want to change the value from a number to text.

 

Desired results:

when plan_id = 1    echo "1 DVD"

when plan_id = 2    echo "2 DVDs"

when plan_id = 3    echo "3 DVDs"

 

$bg = '#ffffff'; //For Initial Row Color

 

  while($row = mysql_fetch_array($result)){

   

    $bg = ($bg=='#ffffff' ? '#e7e8e8' : '#ffffff'); //For Alternate Row Colors

 

  echo '<tr bgcolor="' . $bg . '"><td>' . $row['customers_firstname'] . " " . $row['customers_lastname'] . '</td><td>' . date("M. d, Y", strtotime($row['date'])) . '</td><td>' . if ($row['plan_id'] == 1) {

  echo '1 DVD';

  }

  elseif ($row['plan_id'] == 2) {

  echo '2 DVDs';

  }

  else {

  echo '3 DVDs';

  }

  . '</td></tr>';}

      echo '</table>';

      echo '<br />';

[kenrbnsn]

Try something like this:

<?php
while($row = mysql_fetch_array($result))
{
    $bg = ($bg=='#ffffff' ? '#e7e8e8' : '#ffffff'); //For Alternate Row Colors
    $dvd_string = ($row['plan_id'] == 1)?'DVD':'DVDs';   
    echo "<tr bgcolor='$bg'><td>{$row['customers_firstname']}</td><td>{$row['plan_id']} $dvd_string</td></tr>\n";
}
echo '</table><br />';
?>

 

Ken

[gunthertoody]

Ken,

 

Your code works great, unfortunately, I still need help. What I didn't mention, for the sake of brevity, was that I have 3 more plan_id's and two don't match up. id5 = 6 and id6 =5. That is why I thought that if elseif was the best way to go. I know there's got to be a way, but I'm probably just overlooking proper syntax.

 

David

[cyberRobot]

It's looks like you have an error in the code. This:

 

...
echo '<tr bgcolor="' . $bg . '"><td>' . $row['customers_firstname'] . " " . $row['customers_lastname'] . '</td><td>' . date("M. d, Y", strtotime($row['date'])) . '</td><td>' . 

...

. '</td></tr>';
...

 

Should be:

 

...
echo '<tr bgcolor="' . $bg . '"><td>' . $row['customers_firstname'] . " " . $row['customers_lastname'] . '</td><td>' . date("M. d, Y", strtotime($row['date'])) . '</td><td>';

...

echo '</td></tr>';
...

 

Notice the semicolon after the first echo statement and "echo" was missing from the second.

[gunthertoody]

THANK SO MUCH CYBER, that did the trick. 

 

So I guess the rule is if I start a conditional statement resulting in another echo, I must close out the previous echo statement with a semi-colon?

 

David 

[cyberRobot]

Yep