techker Posted March 6, 2011 Share Posted March 6, 2011 Hey guys i have a blog with images on the side.im doing a script that i can change the images and links to.. i cant seem to figure out how to echo link to image1.. echo (linked_image(table row)'== 'img1') echo (linked_image(table row)'== 'img2') echo (linked_image(table row)'== 'img3').... <? $recent_req2 = "SELECT * FROM $table_m LIMIT 4 , 4"; $res2 = mysql_query($recent_req2); do {?> <div> <a href="<?php echo $link('linked_image'== 'img1');?>"><img src="tmp/1_180x100_v2.gif" alt="" width="180" height="100" /></a> <a href="<?php echo $link['img2']; ?>"><img src="tmp/2_180x100_v2.gif" alt="" width="180" height="100" /></a> <a href="<?php echo $link['img3']; ?>"><img src="tmp/3_180x100_v3.gif" alt="" width="180" height="100" /></a> <a href="<?php echo $link['img4']; ?>"><img src="tmp/4_180x100_v5.gif" alt="" width="180" height="100" /></a> </div> <? } while ($link = mysql_fetch_array($res2)); ?> Quote Link to comment https://forums.phpfreaks.com/topic/229773-while-loop/ Share on other sites More sharing options...
Simmo Posted March 6, 2011 Share Posted March 6, 2011 Not sure exactly what you mean but I would be doing it like this: assuming you have a field in the table called img <?php recent_req2 = "SELECT * FROM $table_m LIMIT 4 "; $res2 = mysql_query($recent_req2); while($img=mysql_fetch_array($res2)){ ?> <a href="img/<?php echo $link['img']; ?>"><img src="img/<?php echo $link['img']; ?>" alt="" width="180" height="100" /></a> <?php } ?> Quote Link to comment https://forums.phpfreaks.com/topic/229773-while-loop/#findComment-1183570 Share on other sites More sharing options...
techker Posted March 6, 2011 Author Share Posted March 6, 2011 well i have a table called link in it i have link_ID linked _IMG and Link so i have 4 pre determed images the querry quets the link table so img 1 in database it is img1 image 2 is img2... (need link in DB)<a href="<?php echo $link('linked_IMG'== 'img1');?>">(image)<img src="tmp/1_180x100_v2.gif" alt="" width="180" height="100" /> </a> <a href="<?php echo $link('linked_IMG'== 'img2');?>">(image)<img src="tmp/1_180x100_v2.gif" alt="" width="180" height="100" />.... Quote Link to comment https://forums.phpfreaks.com/topic/229773-while-loop/#findComment-1183573 Share on other sites More sharing options...
fenway Posted March 7, 2011 Share Posted March 7, 2011 Where's the mysql question? Quote Link to comment https://forums.phpfreaks.com/topic/229773-while-loop/#findComment-1184031 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.