mrt003003 Posted April 6, 2011 Share Posted April 6, 2011 Hi there can anybody help me please? my if statement isnt working?? All i am trying to do is display an image if the session variable is == entered varialble "Empire" I get the error message "Parse error: syntax error, unexpected T_VARIABLE, expecting " if $_SESSION['MM_Username'] == 'Empire'{ echo'<img src="Images/empicon.jpg" width="20" height="20" class="moncalimari"/>' ; } ?> I have checked and the session does == Empire Please help Thank you. Quote Link to comment Share on other sites More sharing options...
mrt003003 Posted April 6, 2011 Author Share Posted April 6, 2011 Oopps, i realise i left out the brackets if ($_SESSION['MM_Username'] == 'Empire'){ echo'<img src="Images/empicon.jpg" width="20" height="20" class="moncalimari"/>' ; } ?> Quote Link to comment Share on other sites More sharing options...
spiderwell Posted April 6, 2011 Share Posted April 6, 2011 never mind Quote Link to comment Share on other sites More sharing options...
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